Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 23)
23.
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
Answer: Option
Explanation:
| 2(A + B + C)'s 1 day's work = |  |
1 | + | 1 | + | 1 |  |
= | 15 | = | 1 | . |
| 30 | 24 | 20 | 120 | 8 |
| Therefore, (A + B + C)'s 1 day's work = | 1 | = | 1 | . |
| 2 x 8 | 16 |
| Work done by A, B, C in 10 days = | 10 | = | 5 | . |
| 16 | 8 |
| Remaining work = | |
1 - | 5 | |
= | 3 | . |
| 8 | 8 |
| A's 1 day's work = | |
1 | - | 1 | |
= | 1 | . |
| 16 | 24 | 48 |
| Now, | 1 | work is done by A in 1 day. |
| 48 |
| So, | 3 | work will be done by A in | |
48 x | 3 | |
= 18 days. |
| 8 | 8 |
Discussion:
61 comments Page 2 of 7.
Vikas kumar said:
3 years ago
LCM = 120.
A=2.5,
B=3.5,
C=1.5.
A + B + C = 7.5 for 10days all works togather then 7.5*10=75,
Remaining=120 - 75 = 45.
For A = 45/2.5 = 18days.
A=2.5,
B=3.5,
C=1.5.
A + B + C = 7.5 for 10days all works togather then 7.5*10=75,
Remaining=120 - 75 = 45.
For A = 45/2.5 = 18days.
(18)
Anandhi said:
1 decade ago
A+B+C one day work = 1/16.
Given B+C = 1/24.
Therefore A+B+C = 1/16.
A+1/24 = 1/16.
A = 1/16-1/24.
A = 1/48.
Given B+C = 1/24.
Therefore A+B+C = 1/16.
A+1/24 = 1/16.
A = 1/16-1/24.
A = 1/48.
(2)
Dinesh said:
1 decade ago
See dude...
ab, bc, ac
So add three (a+b) + (b+c) + (a+c) = so we need (a+b+c).
Add all.
2a + 2b + 2c
2 (a + b + c) = now we add na.
ab, bc, ac
So add three (a+b) + (b+c) + (a+c) = so we need (a+b+c).
Add all.
2a + 2b + 2c
2 (a + b + c) = now we add na.
Phanikiran said:
1 decade ago
What @Naveen kumar said is good and really simple to understand even though it's somewhat long. But no problem. Thank you dude.
Pooja said:
10 years ago
How to solve fractions like 1/30+ 1/24+1/20? Please someone explain in details I am not getting 15/120 as answer please.
Logu said:
1 decade ago
2(A + B + C)'s 1 day's work = 1/8.
Then (A + B + C)'s 1 day's work = 2/8.
How come it is 1/16 ?
Then (A + B + C)'s 1 day's work = 2/8.
How come it is 1/16 ?
Suji said:
1 decade ago
a is not equal to 30...dude
a+b+c=1/16
b+c=1/24
solving above eqn
a+b+c-(b+c)=1/16-1/24..........
a+b+c=1/16
b+c=1/24
solving above eqn
a+b+c-(b+c)=1/16-1/24..........
Pooja said:
10 years ago
How to add fractions like the above one in the questions? I am not getting 15/120 please explain.
Sanjiv said:
9 years ago
Why not like this?
x + 10/48 + 10/80 + 10/60 = 1
Then, we get x = 24 days.
Plese reply for me.
x + 10/48 + 10/80 + 10/60 = 1
Then, we get x = 24 days.
Plese reply for me.
Sanjay said:
8 years ago
They all work togeather when (B+C) on leave then how can we take 10 days work for every person?
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