Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 23)
23.
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
18 days
24 days
30 days
36 days
Answer: Option
Explanation:

2(A + B + C)'s 1 day's work = ( 1 + 1 + 1 ) = 15 = 1 .
30 24 20 120 8

Therefore, (A + B + C)'s 1 day's work = 1 = 1 .
2 x 8 16

Work done by A, B, C in 10 days = 10 = 5 .
16 8

Remaining work = ( 1 - 5 ) = 3 .
8 8

A's 1 day's work = ( 1 - 1 ) = 1 .
16 24 48

Now, 1 work is done by A in 1 day.
48

So, 3 work will be done by A in ( 48 x 3 ) = 18 days.
8 8

Discussion:
61 comments Page 2 of 7.

Subash said:   7 years ago
By approx too we can solve this;

a+b+c=1/10,
b+c=1/24,
a=1/10-1/24,
a=17.13,
Near by value 18.
(5)

VIGNESH said:   8 years ago
Super explanations, thanks @nikhil.

Maruf Hossain said:   8 years ago
Awesome explanation, Thanks @Nikhil.

Mithun said:   8 years ago
GIVEN: A+B B+C A+C.
FORMULA: 2(A+B+C) = (A+B)(B+C)(A+C)
=2(1/8)
=1/16

GET A:
A+B+C=1/16, B+C=1/24.

(A+B+C) - (B+C) =1/16-1/24.

By solving we get A as 1/48.

10/16 + x/48=1 [ABC worked for 10days]
x=18.

Sanjay said:   8 years ago
They all work togeather when (B+C) on leave then how can we take 10 days work for every person?

Damien said:   8 years ago
@Amar.

120 is the LCM of 30, 24 and 20.

Devi said:   8 years ago
Can anyone, please explain easily?

Suman sourav said:   9 years ago
@Kishore.

(a+b + b+c + c=a) = 2(a+b+c).

Dibakar De said:   9 years ago
Very clear explanation. Thanks, @Nikhil.

Suva das said:   9 years ago
How are you get 1/30+ 1/24+ 1/20 = 15/120 = 1/8?

Please someone explain that.


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