Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 10)
10.
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?
Answer: Option
Explanation:
| (P + Q + R)'s 1 hour's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 37 | . |
| 8 | 10 | 12 | 120 |
| Work done by P, Q and R in 2 hours = | ![]() |
37 | x 2 | ![]() |
= | 37 | . |
| 120 | 60 |
| Remaining work = | ![]() |
1 - | 37 | ![]() |
= | 23 | . |
| 60 | 60 |
| (Q + R)'s 1 hour's work = | ![]() |
1 | + | 1 | ![]() |
= | 11 | . |
| 10 | 12 | 60 |
| Now, | 11 | work is done by Q and R in 1 hour. |
| 60 |
| So, | 23 | work will be done by Q and R in | ![]() |
60 | x | 23 | ![]() |
= | 23 | hours 2 hours. |
| 60 | 11 | 60 | 11 |
So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.
Discussion:
96 comments Page 7 of 10.
Shekar said:
1 decade ago
2(1/8+1/10+1/12)+x(1/10+1/12)=1 we get x value is 2.09. required value is 11am+209=1.09pm,we taken approx value 1pm.
Vasanthakumaran P said:
1 decade ago
Hi Friends,
1) P worked from 9 AM to 11 AM (2 hours of work time).
2) In two hours it can print 25,000 books ( Since, 100,000 books in 8 hours it can Print)
3) So remaining 75000 books has to be printed by other two machines (Q and R).
4) Compute the capacity of Q and R, viz : Q+R = ((1/10)+(1/12))= 11/60 = 5.45 hours.
5) So lets put ourself a question. Both the machine needs 5.45 hours to Print 100,000 books. But already 25,000 books has been printed by Machine P. To print remaining 75,000 books Q and R will be needing approximately 4 hours.
Viz; Let x be the number of hours required by Q and R to print 75,000 books.
x = [(5.45*75,000)/100,000] = 4 hours (approximately).
6) All the machines started at 9 Am. Hence 9 + 4 = 13 (1.00 pm).
1) P worked from 9 AM to 11 AM (2 hours of work time).
2) In two hours it can print 25,000 books ( Since, 100,000 books in 8 hours it can Print)
3) So remaining 75000 books has to be printed by other two machines (Q and R).
4) Compute the capacity of Q and R, viz : Q+R = ((1/10)+(1/12))= 11/60 = 5.45 hours.
5) So lets put ourself a question. Both the machine needs 5.45 hours to Print 100,000 books. But already 25,000 books has been printed by Machine P. To print remaining 75,000 books Q and R will be needing approximately 4 hours.
Viz; Let x be the number of hours required by Q and R to print 75,000 books.
x = [(5.45*75,000)/100,000] = 4 hours (approximately).
6) All the machines started at 9 Am. Hence 9 + 4 = 13 (1.00 pm).
Ramkumar said:
1 decade ago
Can anyone tell
Why you put last step as 9am+4?
Already p, q, r done by 2hrs and (q&r) in 4 hrs know.
Then 2+4=6 only know.
On this step I am in confusion. Help me.
Why you put last step as 9am+4?
Already p, q, r done by 2hrs and (q&r) in 4 hrs know.
Then 2+4=6 only know.
On this step I am in confusion. Help me.
Piyus said:
1 decade ago
Friends
P's 2 hr work = 1/8*2=1/4
rest 3/4 work done by q&r
q+r 1hr = 1/10 + 1/12=11/60 work
3/4 work by q&r=60/11 * 3/4=4.09
The work complete time was 9a.m+4=1p.m
P's 2 hr work = 1/8*2=1/4
rest 3/4 work done by q&r
q+r 1hr = 1/10 + 1/12=11/60 work
3/4 work by q&r=60/11 * 3/4=4.09
The work complete time was 9a.m+4=1p.m
Manju said:
1 decade ago
Thanks naveen sir.
Div said:
1 decade ago
Since machine p stops after 37 units of work is completed from 60 units of work, still (60-37=23) 23units of work is remaining. hence, 1-(37/60)= 23/60
Syed said:
1 decade ago
Can some one tell me why 1-37/60 ?
Naveen kumar said:
1 decade ago
Hi friends... In this problem it is having some confusion in the last step....i will explain that step in a easy way....
The work completed by q and r after closing of p machine is
23/60....
but we don't know the time...
we have to calculate it...
(q+r)'s 1 hour work = 11/60.
we can represent the above relation like this....
11/60 (portion of work)-------> 1 hour (time)
23/60 (portion of work) ------> ....? (time)
By cross multiplying the above terms we will get.
11/60 * 60/23 = 23/11
that is approximately equals to 2 ....
q and r machines took 2 hours to complete the remaining work....
i.e.,
11+2 = 1 p.m
the total 1 lakh books will be printed by 1 p.m
The work completed by q and r after closing of p machine is
23/60....
but we don't know the time...
we have to calculate it...
(q+r)'s 1 hour work = 11/60.
we can represent the above relation like this....
11/60 (portion of work)-------> 1 hour (time)
23/60 (portion of work) ------> ....? (time)
By cross multiplying the above terms we will get.
11/60 * 60/23 = 23/11
that is approximately equals to 2 ....
q and r machines took 2 hours to complete the remaining work....
i.e.,
11+2 = 1 p.m
the total 1 lakh books will be printed by 1 p.m
Gayu said:
1 decade ago
Hey is above told methods are applicable? to this type of problems with a small change.
Shashank said:
1 decade ago
Easy Solution
let total time to print the book be x
therefore
x-2/8 + x/10 + x/12= 1
Solve for x we get approx 4
so time will be 9+4=1 pm.
let total time to print the book be x
therefore
x-2/8 + x/10 + x/12= 1
Solve for x we get approx 4
so time will be 9+4=1 pm.
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