Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 10)
10.
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?
Answer: Option
Explanation:
| (P + Q + R)'s 1 hour's work = |  |
1 | + | 1 | + | 1 |  |
= | 37 | . |
| 8 | 10 | 12 | 120 |
| Work done by P, Q and R in 2 hours = | |
37 | x 2 | |
= | 37 | . |
| 120 | 60 |
| Remaining work = | |
1 - | 37 | |
= | 23 | . |
| 60 | 60 |
| (Q + R)'s 1 hour's work = | |
1 | + | 1 | |
= | 11 | . |
| 10 | 12 | 60 |
| Now, | 11 | work is done by Q and R in 1 hour. |
| 60 |
| So, | 23 | work will be done by Q and R in | |
60 | x | 23 | |
= | 23 | hours  2 hours. |
| 60 | 11 | 60 | 11 |
So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M.
Discussion:
95 comments Page 10 of 10.
Sundar said:
9 years ago
Hi, I did it in a way can anyone tell me its right or not.
p = 8, q = 10, r = 12.
Thus, the ratio is 4:5:6.
Work starts at 9.00am and p finish at 11am.
Thus, q can be 12pm and c can be 13pm then the average time will be 13pm, it's 1pm.
Did my assumption is correct? Please give me a suggestion.
p = 8, q = 10, r = 12.
Thus, the ratio is 4:5:6.
Work starts at 9.00am and p finish at 11am.
Thus, q can be 12pm and c can be 13pm then the average time will be 13pm, it's 1pm.
Did my assumption is correct? Please give me a suggestion.
Res said:
9 years ago
How you consider 1hr for (Q + R).
@bhi said:
9 years ago
Reason for 37/120*2 = 37/60?
Divya said:
9 years ago
How do I get this answer 2*1/8 + (1/10) * x + (1/12) x = 1?
x = 4.09.
x = 4.09.
Balu said:
10 years ago
Hello guys, easy solution:
X-2/8 + X/10 + X/12 = 1 (lik A+B+C's 1 Day Work).
By solving we get X = 4.
So, Machines are started at 9.
= 9+4 = 13 (i.e, 1'O clock).
X-2/8 + X/10 + X/12 = 1 (lik A+B+C's 1 Day Work).
By solving we get X = 4.
So, Machines are started at 9.
= 9+4 = 13 (i.e, 1'O clock).
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