Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 22)
22.
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
8 days
10 days
12 days
15 days
Answer: Option
Explanation:

(A + B)'s 1 day's work = ( 1 + 1 ) = 1 .
15 10 6

Work done by A and B in 2 days = ( 1 x 2 ) = 1 .
6 3

Remaining work = ( 1 - 1 ) = 2 .
3 3

Now, 1 work is done by A in 1 day.
15

Therefore 2 work will be done by a in ( 15 x 2 ) = 10 days.
3 3

Hence, the total time taken = (10 + 2) = 12 days.

Discussion:
40 comments Page 3 of 4.

Masud said:   9 years ago
Work per day:

A = 1/15.
B = 1/10.

A work T day = T/15.
B work 2 day = 2/10,

(T/15 + 2/10) = 1.
2T + 6 = 30,
T = 12.

Inna Reddy Chilakala said:   10 years ago
A = 15.

B = 10.

After 2 days B had to leave.

X/15+2/10 = 1.

2X+6 = 30.

2X = 24.

X = 12.

Donald Trump said:   4 years ago
A = 15 = 1/15.
B = 10 =1/10.

1/10 * 2 =1/5.
1-1/5 = 4/5.
1/15 * 4/5 = 12 days.
(3)

Bhaskar said:   1 decade ago
(2/10+2/15) +x/15=1.

Gives x=10.

Hence total days= 10+2=12 Answer.

Pushpendra said:   8 years ago
I think your method was correct & easy. Thanks @Masud.

Abdu Razak said:   10 years ago
Here B done 20%.

So A have to do 80 %.

80 % of 15 = 13.

Vinisha said:   1 decade ago
Why is it 10+2 in the end? why is the 2 days added?

Vidya said:   1 decade ago
Thanks to say another method to me. Keep it up.

Aakansha Goyal said:   5 years ago
Why we add 2 for A's work? Explain please.
(3)

Sunil said:   9 years ago
Why we have to add 2 in the last?


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