Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 22)
22.
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
Answer: Option
Explanation:
| (A + B)'s 1 day's work = |  |
1 | + | 1 |  |
= | 1 | . |
| 15 | 10 | 6 |
| Work done by A and B in 2 days = | |
1 | x 2 | |
= | 1 | . |
| 6 | 3 |
| Remaining work = | |
1 - | 1 | |
= | 2 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 15 |
 |
2 | work will be done by a in | |
15 x | 2 | |
= 10 days. |
| 3 | 3 |
Hence, the total time taken = (10 + 2) = 12 days.
Discussion:
40 comments Page 4 of 4.
Akil Prakash said:
7 years ago
Thank you for the answer @Mr.Aj.
Sona said:
1 decade ago
Why 2 is to be added at the end?
Swathi said:
10 years ago
29x/25-x = 40 find out x value.
Bharathi said:
8 years ago
The work done 6 * 2 = 12 days.
Vivek said:
1 decade ago
2 days already completed so.
Ranjith said:
1 decade ago
A=100/15=6.66%
B=100/10=10%
B=100/10=10%
Sunny said:
9 years ago
@Chinna.
How 1/6 comes?
How 1/6 comes?
Rahul jha said:
1 decade ago
Why we add 10+2 days?
Divya said:
9 years ago
How 1/6 came?
Kapil said:
1 decade ago
How 2/3 came?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers