Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 22)
22.
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in :
Answer: Option
Explanation:
| (A + B)'s 1 day's work = |  |
1 | + | 1 |  |
= | 1 | . |
| 15 | 10 | 6 |
| Work done by A and B in 2 days = | |
1 | x 2 | |
= | 1 | . |
| 6 | 3 |
| Remaining work = | |
1 - | 1 | |
= | 2 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 15 |
 |
2 | work will be done by a in | |
15 x | 2 | |
= 10 days. |
| 3 | 3 |
Hence, the total time taken = (10 + 2) = 12 days.
Discussion:
40 comments Page 2 of 4.
Shyambhai said:
9 years ago
This can be solved by the following method:
(1 - 2/10) * 15 - 2) + 2.
((10 - 2/10) * 15 - 2) + 2.
((8/10) * 15 - 2) + 2.
((4/5 * 15 - 2) + 2.
(12 - 2) + 2.
= 10 + 2 = 12 days --> Answer.
(1 - 2/10) * 15 - 2) + 2.
((10 - 2/10) * 15 - 2) + 2.
((8/10) * 15 - 2) + 2.
((4/5 * 15 - 2) + 2.
(12 - 2) + 2.
= 10 + 2 = 12 days --> Answer.
Sakshi said:
7 years ago
Let the work complete in x days as A's 1-day work is 1/15 (hence his x days work =x/15 and B's 2days work is =2/10.
x/15+2/10=1.
x/15 =1-2/10 .
x/15=4/5.
x=4/5 * 15=12days.
x/15+2/10=1.
x/15 =1-2/10 .
x/15=4/5.
x=4/5 * 15=12days.
(2)
Deepak kumar said:
7 years ago
A=15.
B=10.
Total work 30.
One day A Work 2.
One day B work 3.
So 2 days together work 5*2=10.
So remaining work 30-10 =20.
20/2= 10.
10+2= 12 days answer.
B=10.
Total work 30.
One day A Work 2.
One day B work 3.
So 2 days together work 5*2=10.
So remaining work 30-10 =20.
20/2= 10.
10+2= 12 days answer.
(1)
Mr.AJ said:
1 decade ago
To make it even simple.
A = 1/15;B = 1/10;
B works 2 days = 2/10;
A works y days = y/15;
=>y/15+2/10 = 1.
=>y/15 = 4/5.
So y =12; done.
A = 1/15;B = 1/10;
B works 2 days = 2/10;
A works y days = y/15;
=>y/15+2/10 = 1.
=>y/15 = 4/5.
So y =12; done.
Vinisha said:
1 decade ago
This sum is when B leaves after 2 days, but what is the statement was "B leaves 2 days before the completion of the work? How do you do it?
Arvind said:
1 decade ago
@Kapil.
Total work = 1.
A+B done in 2 days = 1/3.
So remaining = 1-1/3.
= 2/3 :) .
@Mr Aj. Good, well done.
Total work = 1.
A+B done in 2 days = 1/3.
So remaining = 1-1/3.
= 2/3 :) .
@Mr Aj. Good, well done.
Mona said:
6 years ago
A did in 15days.
B did in 10days .
One day work =(1/15 + 1/10) = 1/6.
Total work =1-1/6 = 5/6.
Remaining work: 5/6 * 1/10 = 12.
B did in 10days .
One day work =(1/15 + 1/10) = 1/6.
Total work =1-1/6 = 5/6.
Remaining work: 5/6 * 1/10 = 12.
(2)
Deepak kumar dalabehera said:
9 years ago
B works for 2 days = 1/10 * 2 = 1/5.
Remaining work was done by A = 1 - 1/5 = 4/5.
Total time has taken 4/5 * 15 = 12 days.
Remaining work was done by A = 1 - 1/5 = 4/5.
Total time has taken 4/5 * 15 = 12 days.
Rushil said:
9 years ago
@Kala.
If 20 units are remaining then how you can do 20/2 because A had to do all work. So can you explain me that portion?
If 20 units are remaining then how you can do 20/2 because A had to do all work. So can you explain me that portion?
Chinna said:
1 decade ago
A's 1 day work = 1/15.
B = 1/10.
A+B = 1/15+1/10
= 1/6.
Remaining work = 1-1/6
= 5/6.
= 5/6*1/10.
= 12.
B = 1/10.
A+B = 1/15+1/10
= 1/6.
Remaining work = 1-1/6
= 5/6.
= 5/6*1/10.
= 12.
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