Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 6 of 7.
Bantu Venkatesh said:
6 years ago
15days-----------18days.
5days------------ ?
So, 5/15 * 18 = 6days.
5days------------ ?
So, 5/15 * 18 = 6days.
(3)
Priyanka Sengar said:
5 years ago
@All.
A=18
B=15
B=10
A=?
So 18:15::x:10
X = 12
12 ÷ 2 = 6.
A=18
B=15
B=10
A=?
So 18:15::x:10
X = 12
12 ÷ 2 = 6.
Harsha said:
5 years ago
Nice, Thanks @Siva.
Yakub said:
5 years ago
B one day's work = 1/15
A one day's work = 1/18
B ten day's work = 10/15 = 2/3
Remaining work = 1-2/3 = 1/3
A 's 1/18th work = 1day
A's1/3rd work = 1/3 ÷ 1/18 = 1/3 * 18/1 = 6days.
A one day's work = 1/18
B ten day's work = 10/15 = 2/3
Remaining work = 1-2/3 = 1/3
A 's 1/18th work = 1day
A's1/3rd work = 1/3 ÷ 1/18 = 1/3 * 18/1 = 6days.
(2)
Joel said:
4 years ago
TAKE LCM OF 18 and 15.
LCM = 90
TOTAL WORK=90 UNITS,
A' s one day work=90/18 = 5 units,
B's one day work=90/15 = 6 units,
B's 10 days work=10 days * 6 units = 60 units.
now remaining work= total units-work done by B in 10 days.
i.e, = 90-60= 30 unit of work remaining which is done by A.
A's one-day work is 5 units.
So he completes the remaining 30 units in 6 days(30/5=6 days).
LCM = 90
TOTAL WORK=90 UNITS,
A' s one day work=90/18 = 5 units,
B's one day work=90/15 = 6 units,
B's 10 days work=10 days * 6 units = 60 units.
now remaining work= total units-work done by B in 10 days.
i.e, = 90-60= 30 unit of work remaining which is done by A.
A's one-day work is 5 units.
So he completes the remaining 30 units in 6 days(30/5=6 days).
(2)
Shashidhar B Challamarada said:
4 years ago
Remaining work = (1 - (2/3) ) = 1/3;.
A can finish 1 work in-------> 18 days.
A can finish 1/3 work in--------> x days.
So, x = 18 * (1/3) ;.
X = 6 days.
A can finish 1 work in-------> 18 days.
A can finish 1/3 work in--------> x days.
So, x = 18 * (1/3) ;.
X = 6 days.
(6)
Mehru Qamar said:
4 years ago
Thank you @Shashidhar B Challamarada.
(2)
Nav raj bhatta said:
4 years ago
Easy method:
A = 18.
B = 15.
Now total work = LCM of A & B which is 90,
A's per day work=90/18 = 5
B's per day work=90/15 = 6.
Now B's work in 10 days = 10 * 6 = 60,
Remaining work=90-60 = 30,
Now the time taken by A to finish the remaining work = 30/5 = 6 days.
A = 18.
B = 15.
Now total work = LCM of A & B which is 90,
A's per day work=90/18 = 5
B's per day work=90/15 = 6.
Now B's work in 10 days = 10 * 6 = 60,
Remaining work=90-60 = 30,
Now the time taken by A to finish the remaining work = 30/5 = 6 days.
(42)
Pratik said:
4 years ago
According to questions, A and B both will be working for 10 days right?
Then if we add (1/18 + 1/15) = -ve answer is coming in this way question may be wrong.
Then if we add (1/18 + 1/15) = -ve answer is coming in this way question may be wrong.
(3)
Aniket said:
3 years ago
Let us suppose Total work to be W = 90 units.
(LCM of 15 &18)
According to that,
A's rate of doing work =(90/18)=5 units per day
B's rate of doing work =(90/15)=6 units per day
B worked for 10 days so work done per 10 days would be = 6*10=60 units
Remaining work= 90-60= 30 units
A completes 5 units per day so it will take 6 days to complete the remaining work.
(LCM of 15 &18)
According to that,
A's rate of doing work =(90/18)=5 units per day
B's rate of doing work =(90/15)=6 units per day
B worked for 10 days so work done per 10 days would be = 6*10=60 units
Remaining work= 90-60= 30 units
A completes 5 units per day so it will take 6 days to complete the remaining work.
(38)
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