Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
5

5 1
2

6
8
Answer: Option
Explanation:

B's 10 day's work = ( 1 x 10 ) = 2 .
15 3

Remaining work = ( 1 - 2 ) = 1 .
3 3

Now, 1 work is done by A in 1 day.
18

Therefore 1 work is done by A in ( 18 x 1 ) = 6 days.
3 3

Discussion:
63 comments Page 2 of 7.

Ramkumar said:   1 decade ago
L.C.M=90
b one day capacity is 6
a one day capacity is 5
b work done in 10 days,then 6*10=60
total work(L.C.M)=90-60=30
now,30/a capacity
30/5
=6
(1)

Bala said:   1 decade ago
Answer explained

A's one day work =1/18
B's one day work =1/15

So B worked for 10 days to do a work 1
So B's 10 day work =(1/15)*10 = 10/15 =2/3

B worked only 10 days to complete a work (i.e)1
Therefore remaining work is 1-2/3 =1/3

Now the remaining work is to be completed by A
A's 1 day work is 1/18
To complete 1/3 of work A takes= 1/18*3 = 1/6
Ans 6
(1)

@ankushforbank said:   8 years ago
Rahman Sandeep and Abass can complete a work in 36, 42 and 48 days respectively. Rahman and Sandeep start the work after 6 days they take a leave for few days and handed the work to Abaas. Rahman and Sandeep leave ends 10 days before the work complete and Abass leaves the work on the return of Rahman and Sandeep. Find for how many days Abaas work?

Can anyone solve this time and work problem?

Rohit said:   7 years ago
[A's 1day work = 1/18.

In how many days(x) =1/3 of total work.]
Cross multiplication:
1*1/3=1/18*x
X=6 days.

Ranjit said:   8 years ago
X/18 +10/15 =1.
X+12 = 18,
X = 18 - 12,
= 6 days.

Santhiya' said:   8 years ago
Good explanation. Thank you all.

GHULE ARUN said:   8 years ago
@Ankush

Here is answer for your question.

Take LCM of 36, 42 & 48 i.e. 1008
Now Rehman and Sandeep star work and worked for 6 days.
Now per day work of Rehman = 1008/36 = 28
And per day work of Sandeep = 1008/42=24
Together they have completed per day work = 28+24=52.
Now in 6 days, they completed 52*6 = 312 work out of 1008.
Now last 10 days again Rehman and Sandeep worked so the work completed in 10 days = 52*10=520.
So total work completed by Rehman and Sandeep = 312+520=832.
Remaining work = 1008-832= 176 which is completed by Abbas alone and Abbas per day work is 1008/48= 21.
So Abbas worked for 176/21 Days. Or 8 8/21 days.

Kamu said:   6 years ago
Can't get it. Please explain me clearly.

Shehnaz khatun said:   9 years ago
B + S can do 1 work in 8 days.
B alone can do 1 work in 12 days .

If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?

Kamlesh said:   9 years ago
I did not understand the solution. Can someone please explain in step by step?


Post your comments here:

Your comments will be displayed after verification.