Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
64 comments Page 2 of 7.
Vishnu vardhan said:
4 weeks ago
A = 15.
B = 15.
LCM = 90.
A's one day work = 5
B's one day work= 6
B work for 10 days = 10 * 6 = 60.
remaining = 30.
A's remaining work =Remaining work/A's one day work.
30/5 = 6days.
B = 15.
LCM = 90.
A's one day work = 5
B's one day work= 6
B work for 10 days = 10 * 6 = 60.
remaining = 30.
A's remaining work =Remaining work/A's one day work.
30/5 = 6days.
(1)
Ramkumar said:
1 decade ago
L.C.M=90
b one day capacity is 6
a one day capacity is 5
b work done in 10 days,then 6*10=60
total work(L.C.M)=90-60=30
now,30/a capacity
30/5
=6
b one day capacity is 6
a one day capacity is 5
b work done in 10 days,then 6*10=60
total work(L.C.M)=90-60=30
now,30/a capacity
30/5
=6
(1)
Bala said:
1 decade ago
Answer explained
A's one day work =1/18
B's one day work =1/15
So B worked for 10 days to do a work 1
So B's 10 day work =(1/15)*10 = 10/15 =2/3
B worked only 10 days to complete a work (i.e)1
Therefore remaining work is 1-2/3 =1/3
Now the remaining work is to be completed by A
A's 1 day work is 1/18
To complete 1/3 of work A takes= 1/18*3 = 1/6
Ans 6
A's one day work =1/18
B's one day work =1/15
So B worked for 10 days to do a work 1
So B's 10 day work =(1/15)*10 = 10/15 =2/3
B worked only 10 days to complete a work (i.e)1
Therefore remaining work is 1-2/3 =1/3
Now the remaining work is to be completed by A
A's 1 day work is 1/18
To complete 1/3 of work A takes= 1/18*3 = 1/6
Ans 6
(1)
Sowndarya said:
1 decade ago
Simple & super @Arsh.
Tani said:
10 years ago
Two men can do a piece of work in 6 hours and 4 hours. After the first has worked for 2 hours he is joined by another man. By when should the work be completed?
Can anyone please solve this question. I am facing a lot of problem in this question. This is from composite mathematics. The answer at the back is 1 hour 36 minutes and I am getting 1 hour 33 Minutes.
Can anyone please solve this question. I am facing a lot of problem in this question. This is from composite mathematics. The answer at the back is 1 hour 36 minutes and I am getting 1 hour 33 Minutes.
Kamlesh said:
10 years ago
I did not understand the solution. Can someone please explain in step by step?
Shehnaz khatun said:
10 years ago
B + S can do 1 work in 8 days.
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
B alone can do 1 work in 12 days .
If B alone worked for 4 days and stopped to do. How long will S take to do the remaining work?
@ankushforbank said:
9 years ago
Rahman Sandeep and Abass can complete a work in 36, 42 and 48 days respectively. Rahman and Sandeep start the work after 6 days they take a leave for few days and handed the work to Abaas. Rahman and Sandeep leave ends 10 days before the work complete and Abass leaves the work on the return of Rahman and Sandeep. Find for how many days Abaas work?
Can anyone solve this time and work problem?
Can anyone solve this time and work problem?
Ranjit said:
9 years ago
X/18 +10/15 =1.
X+12 = 18,
X = 18 - 12,
= 6 days.
X+12 = 18,
X = 18 - 12,
= 6 days.
Santhiya' said:
9 years ago
Good explanation. Thank you all.
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