Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 11)
11.
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
Answer: Option
Explanation:
| B's 10 day's work = |  |
1 | x 10 |  |
= | 2 | . |
| 15 | 3 |
| Remaining work = | |
1 - | 2 | |
= | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 |
1 | work is done by A in | |
18 x | 1 | |
= 6 days. |
| 3 | 3 |
Discussion:
63 comments Page 7 of 7.
SHRAVAN LAL said:
10 years ago
A ----- 18 days * 5
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
B ----- 15 days * 6
L.C.M = 90.
B work 10 days and does 10*6 = 60 works.
So left work is 90 - 60 = 30.
A alone does this 30/5 = 6 days.
Very simple.
Ashok said:
9 years ago
Verification of answers:
B can do 10 days work in = 10/15.
A can do one day work = 1/18.
So we can verify the options like to became A+B = 1.
Given That,
B left the work after days so.
10/15+ x*1/18 = 1.
By verifying result: x = 6.
B can do 10 days work in = 10/15.
A can do one day work = 1/18.
So we can verify the options like to became A+B = 1.
Given That,
B left the work after days so.
10/15+ x*1/18 = 1.
By verifying result: x = 6.
Malliga said:
1 decade ago
I can't understand.
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