Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
347 comments Page 3 of 35.

Rakesh said:   1 year ago
1/15+1/20 LCM of this is 60.
So,
(1/15 * 60 + 1/20 * 60)/60we can simplify this you can get (4+3)/60 = 7/60.
(4)

Ashim said:   1 year ago
How 7/60 came? Anyone, please explain to me.
(14)

Sivagami said:   1 year ago
How 7/60 came? Please explain.
(6)

Kalai said:   1 year ago
How remaining work =1? Please explain to me.
(7)

Hemamalini said:   2 years ago
How remaining work =1 ? Please explain me.
(35)

Raghu said:   2 years ago
How 7 comes? Please explain.
(22)

Sowmiya said:   2 years ago
How remaing work =1? Please explain to me.
(20)

Lakshmanan S said:   2 years ago
How come remaining work 1- 7/15? Please explain me.
(71)

Sahil said:   2 years ago
4( 1/15 + 1/20 ) = work done by both of them together

Work Done + Work left =1 =>because the work is 100% completed

4( 1/15 + 1/20 ) + work left = 1;
work left = 1 - (28/ 60);
Then, work left = 8/15;
(66)

Portia said:   2 years ago
How did 1/15 +1/20 turn into 7/60? Someone, please explain.
(43)


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