Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :

1
4

1
10

7
15

8
15

Answer: Option
Explanation:

A's 1 day's work = 1 ;
15

B's 1 day's work = 1 ;
20

(A + B)'s 1 day's work = ( 1 + 1 ) = 7 .
15 20 60

(A + B)'s 4 day's work = ( 7 x 4 ) = 7 .
60 15

Therefore, Remaining work = ( 1 - 7 ) = 8 .
15 15

Discussion:
344 comments Page 2 of 35.

Hari said:   11 months ago
@Vishnu.

Can you explain the process in detail please?
(14)

Vishnu said:   12 months ago
A->15.
B->20.
LCM of 15,20 is 60.
A can do 4 parts and B can do 3 parts.
A and B together complete 7 parts in 1 day.
for 4 days 28 parts can complete.
60-28 = 32(leftover work).
32/60 = 8/15.
(268)

Bha said:   12 months ago
Thanks all for explaining the answer.
(23)

Anonym said:   1 year ago
A, completes the work in 15 days so, the work done by A in 1 day = 1/15.

Similarly, B completes the work in 20 days therefore work done by B in 1 day = 1/20.

A and b work together = 1/15+1/20 i.e. => 14/120 => 7/60.
Now, they both worked for 4 days which will be = 4*7/60 => 7/15.

Let's suppose the total work is x and they have already worked for 4 days.
Therefore remaining work is x -7/15 (for more clarity take x-7/15 = 0) => 8/15.
(25)

John michael said:   1 year ago
15 + 20 = 35,
15 * 20 = 300,
35/300 = 7/60.
(34)

Nitika said:   1 year ago
The reason why we've subtract from 1:

1 represents the whole work or complete work total work considered as 1(or 100%)
(23)

Sugan said:   1 year ago
1 (total work) - 7/15 (together completed work in 4 days).
Lcm = 15 then (15/15 -7/15) = 8/15.
(7)

Rakesh said:   1 year ago
1/15+1/20 LCM of this is 60.
So,
(1/15 * 60 + 1/20 * 60)/60we can simplify this you can get (4+3)/60 = 7/60.
(3)

Ashim said:   1 year ago
How 7/60 came? Anyone, please explain to me.
(14)

Sivagami said:   1 year ago
How 7/60 came? Please explain.
(6)


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