Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 1)
1.
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
Answer: Option
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ![]() |
7 | x 4 | ![]() |
= | 7 | . |
60 | 15 |
Therefore, Remaining work = | ![]() |
1 - | 7 | ![]() |
= | 8 | . |
15 | 15 |
Discussion:
344 comments Page 23 of 35.
Mangu said:
1 decade ago
Let's total total work is 1.
A can do in 15 days.
A can do it in 1 days = 1/15.
Similarly B can do it = 1/20.
They work totally in a day = 1/15+1/20 = 7/60.
A and B do together in 4 days.
So work done in 4 days = 7/60x4 = 7/15.
Then left work is, Total work - 4 days work. i.e, 1-7/15 = 8/7 (Ans).
A can do in 15 days.
A can do it in 1 days = 1/15.
Similarly B can do it = 1/20.
They work totally in a day = 1/15+1/20 = 7/60.
A and B do together in 4 days.
So work done in 4 days = 7/60x4 = 7/15.
Then left work is, Total work - 4 days work. i.e, 1-7/15 = 8/7 (Ans).
Sunita said:
1 decade ago
Why they take like this 1-(7/15)?
Mallarapusudhakar said:
1 decade ago
a = 15, b = 20, together c = 4 but LCM of in this 3 numbers is 60.
So a is 15(4), b is 20(3) and c is 4(15).
The first of 2 function is (4+3) remaining c(15).
The total of LCM(60).
15-7 = 8.
8/60 answer.
So a is 15(4), b is 20(3) and c is 4(15).
The first of 2 function is (4+3) remaining c(15).
The total of LCM(60).
15-7 = 8.
8/60 answer.
Sasi said:
1 decade ago
@Sassy.
First, we have to calculate the work done for 1 day. For that we have to divide the number of days by 1.
So, A's 1 day work = 1/15 and B's 1 day work = 1/20.
Work done by A and B for 1 day is (1/15)+(1/20) = 7/60.
Here, L.C.M is taken.
As per question given, For 4 days, multiple with 4 then we can get.
Work done by A and B for 4 days = 4(7/60) = 7/15.
Here too L.C.M is taken.
Total work is 1(Assumption).
So,Work left = Total work - Work done by A and B.
Therefore, work left = 1-(7/15) = 8/15.
This is the answer.
I hope this helps you.
First, we have to calculate the work done for 1 day. For that we have to divide the number of days by 1.
So, A's 1 day work = 1/15 and B's 1 day work = 1/20.
Work done by A and B for 1 day is (1/15)+(1/20) = 7/60.
Here, L.C.M is taken.
As per question given, For 4 days, multiple with 4 then we can get.
Work done by A and B for 4 days = 4(7/60) = 7/15.
Here too L.C.M is taken.
Total work is 1(Assumption).
So,Work left = Total work - Work done by A and B.
Therefore, work left = 1-(7/15) = 8/15.
This is the answer.
I hope this helps you.
Mounika said:
1 decade ago
Why 300 will come?
Rohit wadile said:
1 decade ago
(a*b)/a+b = work out.
(15*20)/15+20 = 4.
300/35 = 4.
7/15.
Remaining Work = (1-7/15).
Answer = 8/15.
(15*20)/15+20 = 4.
300/35 = 4.
7/15.
Remaining Work = (1-7/15).
Answer = 8/15.
Sassy said:
1 decade ago
I'm not getting it at all can someone explain it why 70/60 in the easiest explanation please.
Srikanth said:
1 decade ago
In all these problems total work taken as "1" so we have to remove the resulting answer i.e., 7/15 from total work"1" so remaining work is (1-7/15) i.e., 8/15.
Deepak said:
1 decade ago
Why are using 1-7/15?
Vikki ls said:
1 decade ago
Hi sir,
How would you calculate the 7/16*4 for to knowing the 4/15=60 ?
Please tell me sir.
How would you calculate the 7/16*4 for to knowing the 4/15=60 ?
Please tell me sir.
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