Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 29)
29.
A and B can do a job together in 7 days. A is 1
times as efficient as B. The same job can be done by A alone in :
times as efficient as B. The same job can be done by A alone in :Answer: Option
Explanation:
| (A's 1 day's work) : (B's 1 day's work) = | 7 | : 1 = 7 : 4. |
| 4 |
Let A's and B's 1 day's work be 7x and 4x respectively.
| Then, 7x + 4x = | 1 |  11x = |
1 | x = |
1 | . |
| 7 | 7 | 77 |
 A's 1 day's work = |
 |
1 | x 7 |  |
= | 1 | . |
| 77 | 11 |
Discussion:
53 comments Page 2 of 6.
Swapna said:
8 years ago
7+4=11......28 ,7....? 11/7*28 = 44 ans.
Yashwanth said:
8 years ago
What will be the answer for same problem with A is twice the efficiency of B?
Bharathi said:
8 years ago
It's easy to understand. Thanks @Kuntal.
Vams'trick said:
8 years ago
B complete work in days = X.
A take days = 4X/7,
A+B work in 1 day = 7/4X + 1/X,
But from problem it is 1/7,
7/4X + 1/X = 1/7,
X =77/4 = B,
A = 4X/7= 4/7 * 77/4 = 11.
A take days = 4X/7,
A+B work in 1 day = 7/4X + 1/X,
But from problem it is 1/7,
7/4X + 1/X = 1/7,
X =77/4 = B,
A = 4X/7= 4/7 * 77/4 = 11.
(1)
Sm Jahid said:
9 years ago
Let,
A do the job = X day.
and B do the job = 7X/4.
By the question,
1/X+4/7X = 1/7,
=> 7+4/7X = 1/7,
=> 7X = 77,
=> X = 11.
So A do the job in 11 days.
A do the job = X day.
and B do the job = 7X/4.
By the question,
1/X+4/7X = 1/7,
=> 7+4/7X = 1/7,
=> 7X = 77,
=> X = 11.
So A do the job in 11 days.
(1)
Vaibhav jain said:
9 years ago
Let,
A = x.
B = 7/4x.
Total work = 7x (i.e. Lcm of A &B).
A's one day work = 7.
B's one day work = 4.
(A + B)'s one day work = 11.
As we know that total work we have 7x.
Using formula of work --->(total work/(A+B) one day work) = (A+B) total work.
7x/11 = 7--->x=7*11/7--> x = 11 i.e total days of x.
A = x.
B = 7/4x.
Total work = 7x (i.e. Lcm of A &B).
A's one day work = 7.
B's one day work = 4.
(A + B)'s one day work = 11.
As we know that total work we have 7x.
Using formula of work --->(total work/(A+B) one day work) = (A+B) total work.
7x/11 = 7--->x=7*11/7--> x = 11 i.e total days of x.
Anil kumar reddy said:
9 years ago
a + b = 7 days.
a = 7/4 * b.
Therefore a + 4/7a - 7 days {since men is inversely proportional to days}.
11a/7 - 7 days for getting a divide with 11/7 and another side multiply with 11/7 then we get 11 days to get complete by alone.
a = 7/4 * b.
Therefore a + 4/7a - 7 days {since men is inversely proportional to days}.
11a/7 - 7 days for getting a divide with 11/7 and another side multiply with 11/7 then we get 11 days to get complete by alone.
ASHRAF said:
9 years ago
Can also do by LCM method A is 1.75 times of effort b ie... 1 3/4 is equal to 1.75...if B is work spree is B then A will be 1.75B is same. So work done by A+B in 7-days is equal to A's work in x days.
So 2.75B * 7 = 1.75B * X,
Solve you get X = 11.
So 2.75B * 7 = 1.75B * X,
Solve you get X = 11.
(1)
Kriti said:
9 years ago
Guys I am not getting the concept of equation 1 and 2 please any one explain me in detail, please.
Juhi said:
9 years ago
If 4/7 of a piece of work is completed in 7/4 days, in how many days can rest of the work be completed?
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