Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 24)
24.
A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in :
4 days
6 days
8 days
18 days
Answer: Option
Explanation:

Ratio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2.

B's 1 day's work = 1 .
12

Therefore A's 1 day's work = 1 ; (2 times of B's work)
6

(A + B)'s 1 day's work = ( 1 + 1 ) = 3 = 1 .
6 12 12 4

So, A and B together can finish the work in 4 days.

Discussion:
28 comments Page 2 of 3.

Amrit said:   7 years ago
suppose B =x;
and A works twice =2x,
then the total amount of work is;
2x+x=12;
3x=12,
x = 4.

Arnab said:   8 years ago
A works twice as fast as B means,

The efficiency of A : B = 2:1 (efficiency means per day work),
A does in 1 day 2 units work.
B does in 1 day 1 unit work.
(A+B) together do in 1 day = 3 units work.

Total work = 1* 12 = 12 units (as per question B can complete a work in 12 days).

(A+B) can do together = 12/ 3 days = 4 days. (Ans.)

Vaishnavi Kokate said:   9 years ago
Let,
A = 20
B = 10 because A works twice as fast as B.

Total work, B = 10 * 12=120 because B completes his work in 12 days.
so A + B/total work.
120/30 = 4 days.

Sudhanshu said:   9 years ago
T --------- W
B --------- 1 1/12
A ---------1 1/6

If A+B work
W --------- T( days)
1/4 --------- 1/1/4.

It comes 4days.

Sudhanshu said:   9 years ago
T --------- W
B --------- 1 1/12
A ---------1 1/6

If A+B work
W --------- T( days)
1/4 --------- 1/1/4.

It comes 4days.

Kashish said:   9 years ago
More easy solution Guys.

Let assume that B take X time, so A will take 2X.

So now there 1 Days work will 1/x + 2/x = 3/x.

Now from question, they work for 12 days,

3/x = 12.
x = 3/12.
x = 4 ->Answer.

Inna Reddy Chilakala said:   10 years ago
A : B = 2 : 1 (work).

B = 12.

A can finish work 1 --- 12.

2 ---- 6.

A+B = 12*6/12+6 = 4.

Deepa said:   1 decade ago
A:B = 1:2.

B can complete a work in 12 days.

Let A can complete in X days.

X:12 = 1:2.
X = 1*12/2.
X = 6 i.e, A = 6.

(A+B) 1 day work = 1/6+1/12 = 1/4.

So, A and B finish work in 4 days.

Aravind_appu said:   1 decade ago
A = 2b------(1).
B = 1/12------(2).

1 sub in 2.

A = 2(1/12).
A = 1/6.

Total work is done TH = A+B.

TH = (1/6+1/12).

= (12+6)/(6*12).
= (18/72).
= 1/4.
= 4 day exactly.

Swati said:   1 decade ago
SHORTCUT:

A is twice efficient as B that means If B takes 12 days then A will take 6 days.
Now both are working together. So definitely together they'll take less than 6 days. ONLY option less than 6 days is Option A i.e. 4 days.


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