Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 26)
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | ; |
| 6 |
| (A + B)'s 1 day's work = | 1 | ; |
| 8 |
| (B + C)'s 1 day's work = | 1 | . |
| 12 |
 (A + C)'s 1 day's work |
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So, A and C together will do the work in 8 days.
Discussion:
53 comments Page 4 of 6.
Akiii said:
1 decade ago
Good explanation.
Sujeet said:
1 decade ago
Why 2 is multiplied by 1/6.
ROHINI said:
1 decade ago
Given a+b=1/8, b+c =1/12, a+b+c =1/6, a+c =?
a+b+c = 1/6.
Sub a+b & b+c in above equ.
1/8 + c = 1/6.
c = 1/24.
a+1/12 = 1/6.
a = 1/12.
a+c = 1/12 +1/24 = 3/24 = 1/8.
a+b+c = 1/6.
Sub a+b & b+c in above equ.
1/8 + c = 1/6.
c = 1/24.
a+1/12 = 1/6.
a = 1/12.
a+c = 1/12 +1/24 = 3/24 = 1/8.
Basu said:
1 decade ago
How its come on 1/6-1/2=1/12
1/6-1/8= 1/24
1/12+1/24= 1/8
1/6-1/8= 1/24
1/12+1/24= 1/8
Nice dreamer said:
1 decade ago
Why 2 is multiplied with 1/6 ? please explain any one.
Nik said:
1 decade ago
1 day's work of(A+B)=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
Dhanshree said:
1 decade ago
(A+B) work is = 1/8.
(B+C)work is = 1/12.
(A+B+C)work is = 1/6.
Only A's work = 1/6-1/12
= 1/12.
Only C's work=1/6-1/8
= 1/24.
Hence (A+C)'s complete work is = (1/12+1/24)
= 1/8.
(A+C)'s complete work in 8 day.
(B+C)work is = 1/12.
(A+B+C)work is = 1/6.
Only A's work = 1/6-1/12
= 1/12.
Only C's work=1/6-1/8
= 1/24.
Hence (A+C)'s complete work is = (1/12+1/24)
= 1/8.
(A+C)'s complete work in 8 day.
Monu said:
1 decade ago
Why can't we simply subtract A+B's 1 day work from B+C's 1 day work to get A+C's 1 day work?
Sk.Gopinath said:
1 decade ago
A+B+C = 1/6;
A+B = 1/8;
B+C = 1/12;
C's 1day work is =>1/6 - 1/8
=>1/24.
A's 1day work is =>1/6 - 1/12
=>1/8.
A+C 's 1day's work =>1/24 + 1/12.
= 1/8 = 8 days.
A+B = 1/8;
B+C = 1/12;
C's 1day work is =>1/6 - 1/8
=>1/24.
A's 1day work is =>1/6 - 1/12
=>1/8.
A+C 's 1day's work =>1/24 + 1/12.
= 1/8 = 8 days.
Parveen verma said:
1 decade ago
(A+B+C)=1/6
A's one day work work= (A+B+C)-(B+C)= 1/6-1/12 =1/12
C's one day work work= (A+B+C)-(A+B)= 1/6-1/8= 1/24
(A+C)'s one day work= 1/12+1/24= 1/8
so the work will be completed in 8 days
A's one day work work= (A+B+C)-(B+C)= 1/6-1/12 =1/12
C's one day work work= (A+B+C)-(A+B)= 1/6-1/8= 1/24
(A+C)'s one day work= 1/12+1/24= 1/8
so the work will be completed in 8 days
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