Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 26)
26.
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in :
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | ; |
| 6 |
| (A + B)'s 1 day's work = | 1 | ; |
| 8 |
| (B + C)'s 1 day's work = | 1 | . |
| 12 |
 (A + C)'s 1 day's work |
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So, A and C together will do the work in 8 days.
Discussion:
54 comments Page 5 of 6.
Nik said:
1 decade ago
1 day's work of(A+B)=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
1 day's work of (B+C)=1/12
lets take 1 day's work of (A+C)=1/x
adding the above we get 2(A+B+C)=1/8+1/12+1/X
dr4 2(1/6)=(1/8)+(1/12)+(1/x)
1/x=(2/6)-(1/8)-(1/12)
1/x=1/8
Suraj said:
1 decade ago
In original solution why they take 1/6*2 from where 2 is occur?
Monu said:
1 decade ago
Why can't we simply subtract A+B's 1 day work from B+C's 1 day work to get A+C's 1 day work?
Sk.Gopinath said:
1 decade ago
A+B+C = 1/6;
A+B = 1/8;
B+C = 1/12;
C's 1day work is =>1/6 - 1/8
=>1/24.
A's 1day work is =>1/6 - 1/12
=>1/8.
A+C 's 1day's work =>1/24 + 1/12.
= 1/8 = 8 days.
A+B = 1/8;
B+C = 1/12;
C's 1day work is =>1/6 - 1/8
=>1/24.
A's 1day work is =>1/6 - 1/12
=>1/8.
A+C 's 1day's work =>1/24 + 1/12.
= 1/8 = 8 days.
Husam said:
1 decade ago
One day's work for (A+B) is 1/8.
One day's work for (B+C) is 1/12.
One day's work for (A+C) is 1/X.
So,
(A+B)+(B+C)+(A+C) = 1/8+1/12+1/x.
2(A+B+C) = 1/8+1/12+1/x.
2*1/6 = 1/8+1/12+1/x.
1/x = 2*1/6-(1/8+1/12).
x = 1/8.
So,
One day's work for (A+C) = 1/8.
A and C finish work in 8 days.
One day's work for (B+C) is 1/12.
One day's work for (A+C) is 1/X.
So,
(A+B)+(B+C)+(A+C) = 1/8+1/12+1/x.
2(A+B+C) = 1/8+1/12+1/x.
2*1/6 = 1/8+1/12+1/x.
1/x = 2*1/6-(1/8+1/12).
x = 1/8.
So,
One day's work for (A+C) = 1/8.
A and C finish work in 8 days.
Nisha said:
1 decade ago
Why 2 is multiplied with 1/6.
To find out (A+C)'s work the equation is 2(A+B+C)-((A+B)+(B+C)).
On solving this equation,
A+B+C = 1/6;
A+B = 1/8;
B+C = 1/12;
(A+C)= 2(1/6)-(1/8+1/12),
= 1/8.
To find out (A+C)'s work the equation is 2(A+B+C)-((A+B)+(B+C)).
On solving this equation,
A+B+C = 1/6;
A+B = 1/8;
B+C = 1/12;
(A+C)= 2(1/6)-(1/8+1/12),
= 1/8.
Hussain said:
1 decade ago
Hey guys please say me.
How 1/12+1/24 = 1/8.
I did not understand the logic the lcm of these two numbers is 24.
How 1/12+1/24 = 1/8.
I did not understand the logic the lcm of these two numbers is 24.
ROHINI said:
1 decade ago
Given a+b=1/8, b+c =1/12, a+b+c =1/6, a+c =?
a+b+c = 1/6.
Sub a+b & b+c in above equ.
1/8 + c = 1/6.
c = 1/24.
a+1/12 = 1/6.
a = 1/12.
a+c = 1/12 +1/24 = 3/24 = 1/8.
a+b+c = 1/6.
Sub a+b & b+c in above equ.
1/8 + c = 1/6.
c = 1/24.
a+1/12 = 1/6.
a = 1/12.
a+c = 1/12 +1/24 = 3/24 = 1/8.
Vick said:
1 decade ago
A's = (A+B+C) - (B+C) = 1/6-1/8 = 1/24.
B's = (A+b+C) - (A+B) 1/6-1/12 = 1/12.
A+C's (1/24) + (1/12) = 1/8.
Therefore they can complete in 8 days.
B's = (A+b+C) - (A+B) 1/6-1/12 = 1/12.
A+C's (1/24) + (1/12) = 1/8.
Therefore they can complete in 8 days.
Mukesh said:
1 decade ago
Any tell me how to solve this sum in L.C.M?
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