Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:
Answer: Option
Explanation:
| (A + B + C)'s 1 day's work = | 1 | , |
| 4 |
| A's 1 day's work = | 1 | , |
| 16 |
| B's 1 day's work = | 1 | . |
| 12 |
 C's 1 day's work = |
1 | - |  |
1 | + | 1 |  |
= | |
1 | - | 7 | |
= | 5 | . |
| 4 | 16 | 12 | 4 | 48 | 48 |
| So, C alone can do the work in | 48 | = 9 | 3 | days. |
| 5 | 5 |
Discussion:
224 comments Page 16 of 23.
Sasi said:
8 years ago
A+b+c-(a+b)=1/4-1/16-1/12=1/4(1/1-1/4-1/3).
4*4**3=48.
=>12-7/48=5/48.
4*4**3=48.
=>12-7/48=5/48.
Amit Bhardwaj said:
8 years ago
Thanks, @Ishwar.
Anurag Singh said:
8 years ago
A work = 16 days.
B work = 12 days.
Total work done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done bye C in one day= 20/4 = 5 unit.
So total work done by C in days = 48/5 days =9*3/5 days.
B work = 12 days.
Total work done by A and B = 48 unit (LCM Of A and B).
So work done by A in one day = 48/16= 3 unit.
And work done by B in one day = 48/12 = 4 unit.
So work done by A and B in 1 day = 3+4 = 7 unit.
Work done by A and B in 4 days = 7*4 = 28 unit.
So remaining work = 48-28 = 20 unit.
So work done bye C in one day= 20/4 = 5 unit.
So total work done by C in days = 48/5 days =9*3/5 days.
Shivam sharma said:
8 years ago
Help here, let's take c's work to be X then (1/16 + 1/12 + 1/X) = 1 but when I find for X by multiplying 4 inside of the bracket. I get a 80/11.
Ved Prakash Singh said:
8 years ago
A's one day work=1/16.
B's one day work=1/12.
Let C can finish the work in x days hence C's one day work=1/x.
A, B and C together can finish the work in 4 days and total work is 1.
4/16+4/12+4/x=1.
so x=48/5 =>9*3/5.
B's one day work=1/12.
Let C can finish the work in x days hence C's one day work=1/x.
A, B and C together can finish the work in 4 days and total work is 1.
4/16+4/12+4/x=1.
so x=48/5 =>9*3/5.
Manish said:
8 years ago
@ALL.
a&b's work for 4 days=7/12.
bal is c work =1-7/12=5/12.
c's 5/12 work in 4 days.
Therefore- 1 work ie 100 % work in how many days?
5/12 in 4 days.
1 in how many days.
4*12/5=48/5 days.
Fraction= 9*3/5.
a&b's work for 4 days=7/12.
bal is c work =1-7/12=5/12.
c's 5/12 work in 4 days.
Therefore- 1 work ie 100 % work in how many days?
5/12 in 4 days.
1 in how many days.
4*12/5=48/5 days.
Fraction= 9*3/5.
Appu said:
8 years ago
Thanks @Aparna.
Vaishu said:
7 years ago
How did 1/4 become total one day's work?
Ritesh Raj said:
7 years ago
@All.
Check this;
A-16d
B-12d
C-xd.
Lcm of all 3=48x(let it be total work that they have to complete).
Now efficiency ( of A,B,C is 3x,4xand 48 resp)
Now. on 1st day all 3 together can do 3x+4x+48 works it is given that they together complete the work in 4 days so;
4*(3x+4x+48)=48 solve it get x, then you will get the answer.
Check this;
A-16d
B-12d
C-xd.
Lcm of all 3=48x(let it be total work that they have to complete).
Now efficiency ( of A,B,C is 3x,4xand 48 resp)
Now. on 1st day all 3 together can do 3x+4x+48 works it is given that they together complete the work in 4 days so;
4*(3x+4x+48)=48 solve it get x, then you will get the answer.
Vikas said:
7 years ago
1/4-7/48= 5/48 how? Please explain.
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