Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 2)
2.
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

9 1 days
5

9 2 days
5

9 3 days
5

10
Answer: Option
Explanation:

(A + B + C)'s 1 day's work = 1 ,
4

A's 1 day's work = 1 ,
16

B's 1 day's work = 1 .
12

Therefore C's 1 day's work = 1 - ( 1 + 1 ) = ( 1 - 7 ) = 5 .
4 16 12 4 48 48

So, C alone can do the work in 48 = 9 3 days.
5 5

Discussion:
224 comments Page 23 of 23.

Tharun A said:   5 months ago
A-----> 16 days.
B ----> 12days.
with the help of C.
AB + C -----> 4 days.
Total work (LCM) = 48.
Efficiency = A-3, B -4, AB + C - 12.
A + B = 7,
AB + C = 12
Then C = 12 - 7 = 5.
C can do work in = Total work/Efficiency = 48/5 = 9*3/5.
(57)

Temesegen demelash said:   4 months ago
Thanks all for helping me to get the answer.
(3)

Ishita Jain said:   3 months ago
Can also be done like this;

(1/16) *4+ (1/12) * 4 + (1/x) * 4 = 1 (as the total work is 1).

Everybody together completes 1/4 of work in one day.

So, (1/4)*4 = 1.
(4)

Ashlyn cicilia said:   3 months ago
Why is 5/48 take as its reciprocal? Please explain to me.
(15)


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