Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
Answer: Option
Explanation:
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, 6x + 8y = | 1 | and 26x + 48y = | 1 | . |
10 | 2 |
Solving these two equations, we get : x = | 1 | and y = | 1 | . |
100 | 200 |
(15 men + 20 boy)'s 1 day's work = | ![]() |
15 | + | 20 | ![]() |
= | 1 | . |
100 | 200 | 4 |
15 men and 20 boys can do the work in 4 days.
Discussion:
202 comments Page 7 of 21.
Mahendra said:
8 years ago
Why are we taking days in x/y form?
Can we solve by 6x+8y=10 doing this if not then why, please help me out?
Can we solve by 6x+8y=10 doing this if not then why, please help me out?
Gopikrishnan said:
8 years ago
Solving these two equations, we get: x =1and y =1.
100 200,
Please explain above the line.
100 200,
Please explain above the line.
Anup S. said:
8 years ago
@Siddharth.
Very well explained.
Very well explained.
Anurag Chachan said:
8 years ago
Answer will be 5.
Nandhini said:
8 years ago
Thanks @Meera.
Bilal khan said:
8 years ago
Please explain 10/100 20/200.
Keshav said:
8 years ago
@Sangeetha.
Please explain this equation and 1/200 how did it come?
6*1/10+8y=1/10.
8y=4/100.
y=1/200.
Please explain this equation and 1/200 how did it come?
6*1/10+8y=1/10.
8y=4/100.
y=1/200.
Naresh said:
8 years ago
The total work is same if take all men and boys are equal then we can write.
(6+8)*10=(15+20)*x.
By solving x=4.
As we know work =eff*time.
(6+8)*10=(15+20)*x.
By solving x=4.
As we know work =eff*time.
Ranjitgh said:
8 years ago
If 10x= 1/10 means. Then x =1, na. How come x=1/100.
Bhavani said:
8 years ago
Thank you for the explanation @Siddharth.
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