Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 6)
6.
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
4 days
5 days
6 days
7 days
Answer: Option
Explanation:

Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.

Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2

Solving these two equations, we get : x = 1 and y = 1 .
100 200

(15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 .
100 200 4

15 men and 20 boys can do the work in 4 days.

Discussion:
201 comments Page 5 of 21.

Shro said:   1 decade ago
Thank you Meera :).

Divya said:   1 decade ago
Thanks siddu and banu.

Sunil Dhiman said:   1 decade ago
Thanks every one to make it easy to understand

Prakash said:   1 decade ago
Why Multiply in 1st equation into 6.

Prajesh said:   1 decade ago
2x+3y=1/10 ----- (1).
3x+2y=1/8 ------ (2).
We want to find: 2x+1y=?---- (3).
Any one can solve this.

Kumudha said:   1 decade ago
Thank you Siddharth, But is this same way to solve same kind of sum.

SSUMEDH said:   1 decade ago
(6Men+8Boy).10=(26Men+48Boy).2
Solve the above equation
1Men=2Boy
15Men+20Boy=25Men

Shubham said:   1 decade ago
Thanks shiddhu.

Sinto Antony said:   1 decade ago
This can be solved with one equation
6 men & 8 boys can do the work in 10 days
Multiply this with 2.5 gives 15 men & 20 boys
Divide the number of days by same factor 2.5 = 10 days / 2.5
i.e. 4 days :)

Hari said:   1 decade ago
We can do this in single step.
6 men and 8 boys can do work in 8 days.

So 6m+8b=1/10
So we have to find 15m+20b=?

6m+8b=1/10.
Divide each term by 2 in both side we get
3m+4b=1/20.

And multiply each term with 5
15m+20b=5*120.
15m+20b=1/4.

So answer is 4 days simple.


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