Aptitude - Time and Work - Discussion

From given data,

6M+8B ---> 10days.
26M+48B ---> 2days.
15M+20B ---> t days.

By using Product approach
WF1*T1=WF2*T2.

(6M+8B)*10=(26M+48B)*2,
4M=8B,
M/B=2/1,
M=2;B=1.

Now substitute We get;
20 --->10 days.
100 --->2 days.
50 ---> t days.
100*2=50*t(Product approach)
t=4 i.e.,4 days.

(6m+8b)*10 = (26m + 48b) * 2.
(6m+8b)*5= (26m + 48b),
20m+40b =26m + 48b.
4m. = 8b,
M/b = 2/1.

Now;
(6*2+8*1) * 10 = (15 * 2 + 20 * 1) * X.
12+8 ) * 10 = (30+20) * X,
200. = 50 * X.
X = 4.

Given:

6M + 8B → 10 days.
26M + 48B → 2 days.

Step 1: Find the Work Ratio of M and B.
Using:
(6M+8B)×10=(26M+48B)×2.

Dividing by 2:
(6M+8B)×5 = 26M + 48B.

Rearrange:
30M + 40B = 26M + 48B
4M = 8B⇒M = 2B.

Step 2: Find Total Work in B Units;
From (6M + 8B) × 10:
(6×2B + 8B) × 10 = 200B,
Total Work = 200B.

Step 3: Find Time for 15M + 20B
Convert 15M into B units:
(15×2B + 20B) × D = 200B,
(30B + 20B)× D = 200B,
50B × D = 200B.
D = 4.

And the Final Answer: 4 days.

2(3m+4b) = 1/10,
3m+4b = 1/20,
5(3m+5b) = ?
= 5×1/20,
= 1/4,
= 4days.

From both conditions, equate total work:

- (6M + 8B) × 10 = (26M + 48B) × 2.
→ 60M + 80B = 52M + 96B,
→ 8M = 16B → M = 2B.
Now convert 15 men + 20 boys into boys:
→ 15 men = 30 boys → Total = 50 boys
Total work = (6M + 8B) × 10 = (12B + 8B) × 10 = 200B,
Time = 200B ÷ 50B = 4 days.

15/6=2.5, 20/8=2.5.
Then , 10(6m and 8b) /2.5=4.

To solve this problem, let's assume:

1 man can do 'm' units of work per day
1 boy can do 'b' units of work per day
Total work is 'W' units.

From the given information, we can form two equations:
Equation 1:
(6m + 8b) * 10 = W

Equation 2:
(26m + 48b) * 2 = W

Solving these equations:
From Equation 1:
60m + 80b = W

From Equation 2:
52m + 96b = W

Setting the equations equal to each other:
60m + 80b = 52m + 96b,
8m = 16b,
m = 2b.

Substituting m = 2b in Equation 1:
60(2b) + 80b = W,
120b + 80b = W,
200b = W,
Now, to find the time taken by 15 men and 20 boys:
(15m + 20b) * t = W.

Substituting m = 2b and W = 200b:
(15 * 2b + 20b) * t = 200b,
(30b + 20b) * t = 200b,
50b * t = 200b.
t = 4 days.
Therefore, 15 men and 20 boys will take 4 days to complete the work.

First convert it to either boys or men's.
(6m+8b)×10=(26m+48B)×2.
8m = 16B,
m=2B.
One man equals 2 boys.

So, use this in any one of the equation, let's take:
= (6m+8B)×10.
= 6(2B)+8B ×10.
= 200B units.

So, use this trick in and find out the work done boys in the given undefined equation:
= 15m + 20B,
= 15(2B) + 20B,
= 50B.

Calculate total work/ work.
= 200B/50B.
= 4 days.

1M = 2BOY.
(15B+20B) = (6M+8B) * 10,
(15M+10M) * DAYS = (6M+4M)*10.
= 4 days is the right answer.

6x+8y = 1/10----------(1)

Taking 2 common on LHS
3x+4y = 1/20,
Multiply it by 5 on both side,
15x+20y = 4.