Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
359 comments Page 4 of 36.
Abdul moeed said:
5 years ago
Use unity rule at the last step,
1/5 work is done in = 3 days.
1 work (whole work) is done in = 3/1/5 = 3*5= 15 days.
1/5 work is done in = 3 days.
1 work (whole work) is done in = 3/1/5 = 3*5= 15 days.
Arun said:
5 years ago
Worker - TotalDay - OneDay
A - 20 - 1/20
B - 30 - 1/30
C - 60 - 1/60
1st Day - A.
2nd Day- B.
3rd Day - A, B, C.
They said A lonely can work for 2 day.
2A = 2(1/20) =1/10.
Then in third day A, B, C together;
(A+B+C) = 1/20+1/30+1/60,
= 1/10.
3 Days(not 3rd Day) work is;
=2A + (A+B+C).
= 1/10+1/10.
3Days =1/5 work,
6Days =2/5 work,
9Days =3/5 work,
12Days=4/5 work,
15Days= 5/5 =1 work completed.
A - 20 - 1/20
B - 30 - 1/30
C - 60 - 1/60
1st Day - A.
2nd Day- B.
3rd Day - A, B, C.
They said A lonely can work for 2 day.
2A = 2(1/20) =1/10.
Then in third day A, B, C together;
(A+B+C) = 1/20+1/30+1/60,
= 1/10.
3 Days(not 3rd Day) work is;
=2A + (A+B+C).
= 1/10+1/10.
3Days =1/5 work,
6Days =2/5 work,
9Days =3/5 work,
12Days=4/5 work,
15Days= 5/5 =1 work completed.
(5)
Sunil_ said:
5 years ago
A work in one day = 1/20,
B work in one day = 1/30,
C work in one day = 1/60.
As A work for 2 days and then on third day B and C do work.
Total work done in three days = A 3 days work+B 1-day work+ C one day work,
= 3/20 + 1/30 + 1/60,
= 9/60 + 2/60 + 1/60
= 12/60.
Total work is done in three days =1/5.
3 = 1/5part.
Let x days required to complete work = 1 part.
3/x = 1/5/1.
x = 3 * 5 = 15 days.
B work in one day = 1/30,
C work in one day = 1/60.
As A work for 2 days and then on third day B and C do work.
Total work done in three days = A 3 days work+B 1-day work+ C one day work,
= 3/20 + 1/30 + 1/60,
= 9/60 + 2/60 + 1/60
= 12/60.
Total work is done in three days =1/5.
3 = 1/5part.
Let x days required to complete work = 1 part.
3/x = 1/5/1.
x = 3 * 5 = 15 days.
(1)
Yoezer said:
5 years ago
3 days 1/5.
6 days 2/5.
9 days 3/5.
12 days 4/5.
15 days 5/5( work completed).
6 days 2/5.
9 days 3/5.
12 days 4/5.
15 days 5/5( work completed).
Britney said:
5 years ago
How did we get 6/60? Anyone explain about it.
(1)
Avinash Singh said:
5 years ago
Here's an easy one:
Let's assume that the total work is done in x days.
Then x/3 days, A will require B and C's help and 2x/3 days A will be working alone.
So the equation becomes:
x/3(1/20) + 2x/3(1/20 + 1/30 + 1/60) = 1 [1 because 1 unit of work is done in x days].
Solve it and you'll get x = 15. Thanks!
Let's assume that the total work is done in x days.
Then x/3 days, A will require B and C's help and 2x/3 days A will be working alone.
So the equation becomes:
x/3(1/20) + 2x/3(1/20 + 1/30 + 1/60) = 1 [1 because 1 unit of work is done in x days].
Solve it and you'll get x = 15. Thanks!
Pooja Pawatekar said:
5 years ago
How can you take A's 2 days work? Can anyone explain this pls?
Kanishk said:
5 years ago
@Keerthi.
We are not directly multiplying.
We just use the unitary method. Here the total work done is 1. In fact, in all these sums total work is 1.
Now,
Since 1/5th of the work is done in 3 days,
Therefore, 1 of the work( whole work) is done in 3*5 days.
Hope you understand.
We are not directly multiplying.
We just use the unitary method. Here the total work done is 1. In fact, in all these sums total work is 1.
Now,
Since 1/5th of the work is done in 3 days,
Therefore, 1 of the work( whole work) is done in 3*5 days.
Hope you understand.
Keerthi said:
5 years ago
why are we multiplying 1/5 *3 in the last step? Please explain anyone.
Hrishi said:
5 years ago
Step 1: Work is done by A+B+C in one day can be calculated as 1/20 + 1/30 + 1/60 = 1/10.
Step 2: For the first two days only A is doing work alone so the work is done by A in two days will be 2*1/20= 1/10.
Step 3: Now total work is done in 3 days by A B & C will be = 1/10+1/10= 1/5.
Step 4: But we need a complete work to be done so we have to convert 1/5 to 1 therefore if we do 1/5 work 5 times then work will be completed (1/5 x 5=1).
Therefore 5 x 3 = 15.
Hope you will understand this solution.
Step 2: For the first two days only A is doing work alone so the work is done by A in two days will be 2*1/20= 1/10.
Step 3: Now total work is done in 3 days by A B & C will be = 1/10+1/10= 1/5.
Step 4: But we need a complete work to be done so we have to convert 1/5 to 1 therefore if we do 1/5 work 5 times then work will be completed (1/5 x 5=1).
Therefore 5 x 3 = 15.
Hope you will understand this solution.
(1)
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