Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 33 of 36.
Balaram said:
1 decade ago
Thank you everybody for participating in the discussion and making clarification for all my unanticipated doubts.... Nikita Prasad gave good explanation.
Fathi said:
1 decade ago
Awesome explanation nikitha! this is Wat I was searching for:-).
ROSE said:
1 decade ago
Work done in 3days=1/10(A'S 2DAYS WORK)+1/10(1DAY WORK FROM ABC)
=2/10=1/5
NOW CROSS MULTIPLY FOR 1/5 3DAYS ARE REQUIRED FOR 5/5 DAYS HOW MANY DAYS ARE REQUIRED
NOW 5/5=1
1*3/1/5=
3*5/1=15
=2/10=1/5
NOW CROSS MULTIPLY FOR 1/5 3DAYS ARE REQUIRED FOR 5/5 DAYS HOW MANY DAYS ARE REQUIRED
NOW 5/5=1
1*3/1/5=
3*5/1=15
Shreya said:
1 decade ago
I dint get how did you multiply 5*3. It was 1/5 83?
Ramesh said:
1 decade ago
Nice explanation nikitha:-)
Nitinkumar said:
1 decade ago
A+B+C=(1/20)+(1/30)+(1/60)=1/10
ON 3 RD DAY HE IS TAKING WORK FROM BOTH B&C HIS 2DAYS WORK +A+B+C WORK= 1/10+1/10 = 2/10 =1/5
MULTIPLY WIT 1/3 U LL GET 1/15
15 DAYS
ON 3 RD DAY HE IS TAKING WORK FROM BOTH B&C HIS 2DAYS WORK +A+B+C WORK= 1/10+1/10 = 2/10 =1/5
MULTIPLY WIT 1/3 U LL GET 1/15
15 DAYS
Sindu said:
1 decade ago
Why in the last step 3 is multiplied with 5?
Niket said:
1 decade ago
Actually in 3rd step work done by A on 3rd day was not added that's why the answer became 15 days.
Manoj shukla said:
1 decade ago
Why 3*5?
Suneel kumar said:
1 decade ago
Why you multiply 3*5?
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