Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
362 comments Page 33 of 37.
Sathish said:
2 decades ago
Hi friends,
we know that whole work completed means we will denote it as 1(full)....
2=1(in 2days full work get completed)
5=1(in 5days full work get completed)
just simple 5=1/2 =>5*2=1(just cross multiple the 2)
we know that whole work completed means we will denote it as 1(full)....
2=1(in 2days full work get completed)
5=1(in 5days full work get completed)
just simple 5=1/2 =>5*2=1(just cross multiple the 2)
Benny said:
2 decades ago
Here my simple ans:
A is working continue 2 day's.So he's 2day's work is:1/20*2=1/10;
in 3rd day he join other two person B and C.So here 3 member work:
1/20+1/30+1/60=1/10;
3 day's work is :1/0+1/10=1/5
So total work done by them is 10+5=15;
A is working continue 2 day's.So he's 2day's work is:1/20*2=1/10;
in 3rd day he join other two person B and C.So here 3 member work:
1/20+1/30+1/60=1/10;
3 day's work is :1/0+1/10=1/5
So total work done by them is 10+5=15;
(1)
Sindhu said:
2 decades ago
@Baskar
Can you please explain me why do you cross multiply at the end for the answer?
Can you please explain me why do you cross multiply at the end for the answer?
Kumar said:
2 decades ago
Can you please tell me how you get 6/60?
Arpit Mathur said:
2 decades ago
Hey please explain why A's 2 day work is taken?
Balaram said:
2 decades ago
Thank you everybody for participating in the discussion and making clarification for all my unanticipated doubts.... Nikita Prasad gave good explanation.
Fathi said:
2 decades ago
Awesome explanation nikitha! this is Wat I was searching for:-).
ROSE said:
2 decades ago
Work done in 3days=1/10(A'S 2DAYS WORK)+1/10(1DAY WORK FROM ABC)
=2/10=1/5
NOW CROSS MULTIPLY FOR 1/5 3DAYS ARE REQUIRED FOR 5/5 DAYS HOW MANY DAYS ARE REQUIRED
NOW 5/5=1
1*3/1/5=
3*5/1=15
=2/10=1/5
NOW CROSS MULTIPLY FOR 1/5 3DAYS ARE REQUIRED FOR 5/5 DAYS HOW MANY DAYS ARE REQUIRED
NOW 5/5=1
1*3/1/5=
3*5/1=15
Shreya said:
2 decades ago
I dint get how did you multiply 5*3. It was 1/5 83?
Ramesh said:
2 decades ago
Nice explanation nikitha:-)
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