Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
359 comments Page 32 of 36.
Ganbrave said:
1 decade ago
@Poornima
A works for 2 days and B,C joins him on 3rd day.
so total combination of them is now 3days
Based on these 3days we can furthur calculate..ok??
A's 2 days work=1/10 and on 3rd day A,B,C together work=1/10
So sum of them gives u total 3days of work done by all of them.
A works for 2 days and B,C joins him on 3rd day.
so total combination of them is now 3days
Based on these 3days we can furthur calculate..ok??
A's 2 days work=1/10 and on 3rd day A,B,C together work=1/10
So sum of them gives u total 3days of work done by all of them.
Poornima said:
1 decade ago
How can you taking that 3 days? and 1/10+1/10 what is it ?
Anil said:
1 decade ago
Thanks benny.
Manoj said:
1 decade ago
i.e;
3 days =1/5
6 days=2/5
9 days=3/5
12 days=4/5
15 days=5/5(1)==work completed
3 days =1/5
6 days=2/5
9 days=3/5
12 days=4/5
15 days=5/5(1)==work completed
(1)
Harry said:
1 decade ago
1.)days worked by A is 2; 1 day helped by B and C and not A,
2.)given is A's 3 day work
3.)total 1 day work of A,B,C is find
4.)A's 2 day work is found
Result calculation:
A's 3day work=>(1/10)+(1/10)=>A 2day work+A,B,C's 1days)
=>1/5(of whole work) [5 is n]
A's whole work=3*5=15days
2.)given is A's 3 day work
3.)total 1 day work of A,B,C is find
4.)A's 2 day work is found
Result calculation:
A's 3day work=>(1/10)+(1/10)=>A 2day work+A,B,C's 1days)
=>1/5(of whole work) [5 is n]
A's whole work=3*5=15days
Neetu singh said:
1 decade ago
@benny-reli nice explanation.
Preethi said:
1 decade ago
1/5 of work being done in 3 days. But how do we arrive at the total no. Of days worked by A? what is the logic behind?
Sathish said:
1 decade ago
Hi friends,
we know that whole work completed means we will denote it as 1(full)....
2=1(in 2days full work get completed)
5=1(in 5days full work get completed)
just simple 5=1/2 =>5*2=1(just cross multiple the 2)
we know that whole work completed means we will denote it as 1(full)....
2=1(in 2days full work get completed)
5=1(in 5days full work get completed)
just simple 5=1/2 =>5*2=1(just cross multiple the 2)
Benny said:
1 decade ago
Here my simple ans:
A is working continue 2 day's.So he's 2day's work is:1/20*2=1/10;
in 3rd day he join other two person B and C.So here 3 member work:
1/20+1/30+1/60=1/10;
3 day's work is :1/0+1/10=1/5
So total work done by them is 10+5=15;
A is working continue 2 day's.So he's 2day's work is:1/20*2=1/10;
in 3rd day he join other two person B and C.So here 3 member work:
1/20+1/30+1/60=1/10;
3 day's work is :1/0+1/10=1/5
So total work done by them is 10+5=15;
(1)
Sindhu said:
1 decade ago
@Baskar
Can you please explain me why do you cross multiply at the end for the answer?
Can you please explain me why do you cross multiply at the end for the answer?
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