Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
362 comments Page 34 of 37.
Nitinkumar said:
2 decades ago
A+B+C=(1/20)+(1/30)+(1/60)=1/10
ON 3 RD DAY HE IS TAKING WORK FROM BOTH B&C HIS 2DAYS WORK +A+B+C WORK= 1/10+1/10 = 2/10 =1/5
MULTIPLY WIT 1/3 U LL GET 1/15
15 DAYS
ON 3 RD DAY HE IS TAKING WORK FROM BOTH B&C HIS 2DAYS WORK +A+B+C WORK= 1/10+1/10 = 2/10 =1/5
MULTIPLY WIT 1/3 U LL GET 1/15
15 DAYS
Sindu said:
2 decades ago
Why in the last step 3 is multiplied with 5?
Niket said:
2 decades ago
Actually in 3rd step work done by A on 3rd day was not added that's why the answer became 15 days.
Manoj shukla said:
2 decades ago
Why 3*5?
Suneel kumar said:
2 decades ago
Why you multiply 3*5?
Divya said:
2 decades ago
Chitra its very clear.
Hamsa said:
2 decades ago
How did you get 6/60 could you please clarify?
Rajasekhar said:
2 decades ago
The question does'nt mean to find the 3 days work how we can solve this for 3 days work?.
Poonam said:
2 decades ago
Please give altarnate methad to solve this question, then we know wether the ans you got is right or wrong.
Manasa said:
2 decades ago
@nikita prasad. You just rock. Good explanation with logic. :-) ).
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