Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 21 of 36.

Raman said:   1 decade ago
"A" can complete work in 20 days.

A's 1 day work is 1/20.

A's 2 days work is 2/20.

A's first day + A's second day + (A + B + C).

=> 1/20+1/20/+ (1/20+1/30+1/60).

=>2/20+ (1/20+1/30+1/60).

=>2/20+1/10 = 1/5.

So 3 days work = 1/5 convert it to one day work.

3/1/5 = 5/1*3 = 5*3 = 15 days.

Other way:

= 1/5 in three days we want to finish work.

= 1/5 + 1/5 + 1/5 + 1/5 + 1/5 = 5/5 = work finished.

Sunil said:   1 decade ago
@Nikita answer is fantastic.

Farha said:   1 decade ago
The question is not about to ask the work of 3 days. Then why we are finding 3 days's work.

Can anybody explain, I am so confused.

A govardhan reddy said:   1 decade ago
A can do 20 days so = 1/20.

A can do with B and C every third day = 20/3 = 18+2 (alone).

A+B+C = (3/18+1/30+1/60) = 1/5.

So the A work done in three days = 5*3 = 15 days.

Ram said:   1 decade ago
Last step:

1/5 work = 3 days.

W/5 = 3d.
W = 3*5d.
W = 15d.

Full work = 15 days.

Veda said:   1 decade ago
"A" can complete work in 20 days.

A's 1 day work is 1/20.

A's 2 days work is 2/20.

According to the question A work for 2 day's and on the third day.

B & C assists (**helps, not replaced).

So it goes like this.

A's first day + A's second day + (A + B + C) on third day, B & C helped.

i.e 2 1/20+1/20/+(1/20+1/30+1/60).

=>2/20+(1/20+1/30+1/60).

=>2/20+1/10.

= 1/5.

So for first 2 days and combining B and C on third day they will work 1/5th of a work.

All together (A+A+ (A+B+C) ) works for 3 days to get 1/5th of a work so.

If 1/n work is done in 1 days total work is done in 1*n = n days.

The same here, if 1/5 work is done in 3 days total work is done in 5*3 = 15 days.
(1)

Trinadh said:   1 decade ago
1/20, 1/30, 1/60.

Add 1/3 to the ends of both B and C.

= 1/20+1/30*3+*1/60*3.

= 1/15.

Sindhu said:   1 decade ago
@Ashwini.

As they mentioned in the question A is assisted B and C on every third day means on every third day A B C do the work together. That means you have to add A B C 's one day work.

i.e 1/20+1/30+1/60 = 6/60 = 1/10.

Animesh said:   1 decade ago
A 20--------------------3.
B 30 ---LCM 60 -------2.
C 60--------------------1.

Total = 3+2+1 = 6.
So answer = 60/6 = 10.

Ashwini said:   1 decade ago
Can you explain how 6/60 came?


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