Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
| A's 2 day's work = |  |
1 | x 2 |  |
= | 1 | . |
| 20 | 10 |
| (A + B + C)'s 1 day's work = | |
1 | + | 1 | + | 1 | |
= | 6 | = | 1 | . |
| 20 | 30 | 60 | 60 | 10 |
| Work done in 3 days = | |
1 | + | 1 | |
= | 1 | . |
| 10 | 10 | 5 |
| Now, | 1 | work is done in 3 days. |
| 5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 13 of 36.
Shakti said:
1 decade ago
Last step. 1/5th of work completed in 3 days.
We have to find 1 or whole work can completed in how many days.
1/5th work= 3 days.
1 work= 3/ (1/5) = 3*5= 15 days.
We have to find 1 or whole work can completed in how many days.
1/5th work= 3 days.
1 work= 3/ (1/5) = 3*5= 15 days.
Vinay vidhani said:
1 decade ago
Please tell me some one where I'm doing mistake.
Hear A can do a work in 20 days B-30 days and C doing in 60 days.
A's 3 day work is 1/20*3.
B's work will be on 3rd day is 1/90 and C's - 1/180 they work together then answer is coming 6 days please tell about that's solution soon please.
Hear A can do a work in 20 days B-30 days and C doing in 60 days.
A's 3 day work is 1/20*3.
B's work will be on 3rd day is 1/90 and C's - 1/180 they work together then answer is coming 6 days please tell about that's solution soon please.
Narayana said:
1 decade ago
A work in 2 Days = 1/20*2 = 1/10.
After 3rd day add in B, C. So A, B, C work in 1 day.
= 1/20+1/30+1/60 = 1/10.
2days + 1 day = 1/10+1/10 => 1/5.
Work completed = 1/5*3 = 15 days.
After 3rd day add in B, C. So A, B, C work in 1 day.
= 1/20+1/30+1/60 = 1/10.
2days + 1 day = 1/10+1/10 => 1/5.
Work completed = 1/5*3 = 15 days.
Karthikeyan said:
1 decade ago
Please explain me the lcm method for this problem.
Arun said:
1 decade ago
Can you explain the 3rd step please?
Chaaya said:
1 decade ago
Can anybody explain me why 5 is multiplied by 3 at the end??
Nirav said:
1 decade ago
@chaaya:
1/5 work done in no. of days= 3
1 work done in no. of days= ?
so it is 3/(1/5)= 3*5=15
1/5 work done in no. of days= 3
1 work done in no. of days= ?
so it is 3/(1/5)= 3*5=15
Netra said:
1 decade ago
Please tell me why they have multiplied 3 day's work with 5.
Trisha said:
1 decade ago
Whole work will be done in (3 x 5) = 15 days.
I m unable to understand a last step. Explain me?
How they multiply by 5?
I m unable to understand a last step. Explain me?
How they multiply by 5?
Durga said:
1 decade ago
LCM of 20,30,60 is 600
A's work is 600/20
if b and c on third day then 2 days(first and second) for A and 1 day for B and c(third day)
so A's work is 600/(20*2)=600/40=15
A's work is 600/20
if b and c on third day then 2 days(first and second) for A and 1 day for B and c(third day)
so A's work is 600/(20*2)=600/40=15
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