Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 12 of 36.

Bralow said:   1 decade ago
Why we multiply 3*5 in last step?

Sandya said:   1 decade ago
@ nikita prasad

Its really good explanation. I had lot more confusion at this step. Now I'm clear. ThanQ.

Yogendra said:   1 decade ago
Thanks nikithas & bhaskar for your nice explanation.

Preethi said:   1 decade ago
Why we are takng 3*5 in last step please expain.

Raju said:   1 decade ago
Why we are takng 3*5 in last step please expain.

Karthik said:   1 decade ago
@Preethi.

3*5 because 1/5*5 gives you 1 which means the work has been completed. So 1/5 is derived for work done in 3 days. Understood ah.

Kranthi said:   1 decade ago
A's 1 day work = 1/20
B every 3 days = 3/30
C also every 3 days = 3/60
Total work = 1/20+3/30+3/60
= 3+6+3/60 = 12/60 =1/5
3*5 days=full work completed
15
Is it correct way

Anonymous said:   1 decade ago
Why do you need to find A's work in 2 days?

Kumar said:   1 decade ago
@Preethi
Finally we got the answer 1/5->work completed in 3 days clear upto here.Coming to your doubt we have to know the full work completed in no of days 1/5th work == 3days=1/5th work Just make above Rhs as 1 Full work == 3*? =1/5*5
== 3*5 =1/5*5
1 Full work in 15 days == 15 =1
Hope your doubt is cleared.

Tuhin said:   1 decade ago
EASY WAY FOR THIS QUESTION :

Let total no. of days be= N
Work done by A,B,C respectively per day are :1/20,1/30,1/60
As B and C join every third day there work done by them :(N/3)/30 and (N/3)/60 respectively.
And for A : N/20
Total work=
N/20+(N/3)/30+(N/3)/60=1

We get N as 15


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