Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 5)
5.
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
Answer: Option
Explanation:
| C's 1 day's work = | 1 | - |  |
1 | + | 1 |  |
= | 1 | - | 7 | = | 1 | . |
| 3 | 6 | 8 | 3 | 24 | 24 |
| A's wages : B's wages : C's wages = | 1 | : | 1 | : | 1 | = 4 : 3 : 1. |
| 6 | 8 | 24 |
 C's share (for 3 days) = Rs. |
|
3 x | 1 | x 3200 | |
= Rs. 400. |
| 24 |
Discussion:
184 comments Page 4 of 19.
Shivani kumari said:
6 years ago
A's 3day ways = (1/6)*3*3200 = 1600.
B's 3day ways = (1/8)*3*3200 = 1200.
C's 3day ways = 3200-(1600+1200).
B's 3day ways = (1/8)*3*3200 = 1200.
C's 3day ways = 3200-(1600+1200).
(6)
Sai said:
7 years ago
A = 6days.
B = 8days.
A+B+C=3days.
C's no of days required to complete the work.
(1÷6)+(1÷8)+(1÷C)=(1÷3).
Therefore C=24 day's.
Now the ratio of no of days taken by each member to complete the work comes(6:8:24).
But, we know that A is somewhat a fast worker than B and C therefore he must be paid more and C is taking more time he must be paid less,
Now let's considers these people's each day of work ie A=(1÷6), B=(1÷8), C=(1÷24).
Therefore the total units of work=(1÷6)+(1÷8)+(1÷24)=( 1÷3) by taking lcm
Now ,
The total amount to is 3200.
3200/(1÷3)=9600.
Therefore 9600/24 is 400.
B = 8days.
A+B+C=3days.
C's no of days required to complete the work.
(1÷6)+(1÷8)+(1÷C)=(1÷3).
Therefore C=24 day's.
Now the ratio of no of days taken by each member to complete the work comes(6:8:24).
But, we know that A is somewhat a fast worker than B and C therefore he must be paid more and C is taking more time he must be paid less,
Now let's considers these people's each day of work ie A=(1÷6), B=(1÷8), C=(1÷24).
Therefore the total units of work=(1÷6)+(1÷8)+(1÷24)=( 1÷3) by taking lcm
Now ,
The total amount to is 3200.
3200/(1÷3)=9600.
Therefore 9600/24 is 400.
Princi said:
7 years ago
What is the need of ratio?
HARIPRASAD K N said:
7 years ago
It is very simple;
A's 1day work = 1/6.
B's 1day work = 1/8.
A&B&C's 1day work=1/3.
C's 1day work=A+B+C'S 1day work-(A+B's 1day work)=(1/3)-(1/6)-(1/8) = 1/24.
A will do a complete work that is 1 full work in 6 day's means how much work he will do in 3 days given by;
6days--------->1 complete work
3days--------->?
Cross multiply then we get 1/2 work that is half of the work total work done by A.
Similarly, B ' s work done in 3 days is given by;
8 days-------->1 complete work,
3------------------?
Cross multiply we get 3/8 part of 1 complete work done by B.
Similarly, C's part of work is given by;
24 days --------->1 complete work
3 days ------------>?
By cross multiply, we get 1/8.
So,
For 1 complete work they get ------------>3200.
Then for A's (1/2) part of that work------>?
Cross multiply we get 1600.
Similarly for B
1 complete work------->3200
B's (3/8) part of the work--->?
By cross multiply, we get 1200.
Similarly for C.
1 Complete work ------>3200
C's part of (1/8) part of the work--->?
We get by cross multiply 400.
A's 1day work = 1/6.
B's 1day work = 1/8.
A&B&C's 1day work=1/3.
C's 1day work=A+B+C'S 1day work-(A+B's 1day work)=(1/3)-(1/6)-(1/8) = 1/24.
A will do a complete work that is 1 full work in 6 day's means how much work he will do in 3 days given by;
6days--------->1 complete work
3days--------->?
Cross multiply then we get 1/2 work that is half of the work total work done by A.
Similarly, B ' s work done in 3 days is given by;
8 days-------->1 complete work,
3------------------?
Cross multiply we get 3/8 part of 1 complete work done by B.
Similarly, C's part of work is given by;
24 days --------->1 complete work
3 days ------------>?
By cross multiply, we get 1/8.
So,
For 1 complete work they get ------------>3200.
Then for A's (1/2) part of that work------>?
Cross multiply we get 1600.
Similarly for B
1 complete work------->3200
B's (3/8) part of the work--->?
By cross multiply, we get 1200.
Similarly for C.
1 Complete work ------>3200
C's part of (1/8) part of the work--->?
We get by cross multiply 400.
(1)
Yaamu said:
7 years ago
Why we are taking ratio 3 * 3200 * 1/24 where does this 3 come from can anyone explain me?
(2)
Zeenat said:
7 years ago
1/6 * 24 : 1/8 * 24 :1/24 * 24 convert fraction to the whole number.
Ishan raj said:
7 years ago
How 4:3:1 came? Anyone explain me.
(1)
Praveen kumar said:
7 years ago
The sum of three numbers is 275. If the ratio between the fast and second be 3:7 and that between the second and third be 4:5 then find the second number. Can anyone solve this?
Sruthi said:
7 years ago
The total work-> 24 {LCM of days}.
A's 1day work->4,
B's 1day work->3,
with the help of C they completed the work in 3 days,
A+B+C=8 {24/3 ie, total work/no.of days to complete}.
4+3+C=8.
C=1.
Then, 3200/8=400.
C does 1unit so C gets 400.
If it does 2units 400 * 2.
A's 1day work->4,
B's 1day work->3,
with the help of C they completed the work in 3 days,
A+B+C=8 {24/3 ie, total work/no.of days to complete}.
4+3+C=8.
C=1.
Then, 3200/8=400.
C does 1unit so C gets 400.
If it does 2units 400 * 2.
(1)
Vidyasri said:
7 years ago
Thank you @Sai vinay.
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