Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 8 of 10.
Abhilash said:
1 decade ago
How to solve alternative working days problem in time and work?
Priti said:
8 years ago
Please tell me how to solve the equation of x and y in detail?
Mona said:
9 years ago
How we are getting 1 in the equation 16x+44y please Explain.
SRI said:
9 years ago
1/30 - 1/16 = 7/240
2*1 / 44 = 1/22
7/240 - 1/22 = 43/2640
2*1 / 44 = 1/22
7/240 - 1/22 = 43/2640
SHEIK said:
1 decade ago
@Kanna
Your explanation is good and easily understandable.
Your explanation is good and easily understandable.
Sunil kumar said:
1 decade ago
Why can't we take 1/x, 1/y instead of x, y as one day work?
Neha said:
10 years ago
@Varun how you take 26.66%?
Can you explain me please?
Can you explain me please?
Gamvir said:
5 years ago
Average work = 60.
A = 16/60 = 4/15.
B=11/15*1/44=60.
A = 16/60 = 4/15.
B=11/15*1/44=60.
(5)
Thangeswari said:
1 decade ago
Kanna.
Thanks a lot. Your explanation was excellent.
Thanks a lot. Your explanation was excellent.
Naseem Ahmad Saifi said:
10 years ago
There is no short cut for this @Ram is correct.
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