Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 9 of 10.
Pandit said:
1 decade ago
@Kanna.
You explain very easly. Thanks a lot.
You explain very easly. Thanks a lot.
Student said:
1 decade ago
How can we write 16x+44y=1. I cant understand.
(1)
Shyam said:
1 decade ago
I got the same answer as Sai and Kaustubha.
Jitender said:
10 years ago
I want any short method of this question.
Bisu said:
9 years ago
Can somebody solve it in the shortcut?
Kaavya said:
7 years ago
Thanks for the answer @Tapash Dey.
Bangaram said:
1 decade ago
Kanna your explaination was good.
Santh said:
1 decade ago
Selvi. You are wrong absolutely.
(1)
Soniya said:
1 decade ago
@kanna.
You are right. Thanks.
You are right. Thanks.
Yogi said:
1 decade ago
@Manasa
Yes you are corrrect.
Yes you are corrrect.
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