Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
30 days
40 days
60 days
70 days
Answer: Option
Explanation:

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1 and 16x + 44y = 1.
30

Solving these two equations, we get: x = 1 and y = 1
60 60

B's 1 day's work = 1 .
60

Hence, B alone shall finish the whole work in 60 days.

Discussion:
97 comments Page 8 of 10.

Bangaram said:   1 decade ago
Kanna your explaination was good.

Akiii said:   1 decade ago
Kanna you are right.

Vishal said:   1 decade ago
Above solution is not properly explained.

Let me try to make it more clear (mathematically or logically).

1 day = 24 Hours.
A worked x hours in 1 day (24 hours).
B worked y hours in 1 day (24 hours).

So, x + y = 24 hours ----- Eq 1.

Now A's 16 days' work in hours = 16 * x = 16x.

And B's 44 days' work in hours = 44 * y = 44y.

16x + 44y = 30 days together worked of A + B in hours = 30 * 24 = 720 hours.

So 16x + 44y = 720 ----- Eq 2.

Now Eq 2 - 16 * Eq 1.

16x + 44y = 720.
16x + 16y = 384.
0 + 28y = 336.

Y = 336 / 28 = 12 hours in 1 day.

So x = 12 hours in 1 day.

If A doesn't work then to B has to work 24 hours in order to finish 1 day work which is equal to 2 days for B.

So for 30 days work, B has to work 60 days (answer = 60 days).

Guest said:   2 decades ago
Selvi: its wrong... because, we dont know a & b's one day work.

Sunil kumar said:   1 decade ago
Any easy method better than above all? All are did in same method. Somehow tough above all the methods.

Ray said:   10 years ago
I have figure out the easiest way to understand the equation:

Let's say the speed of work done by each A and B in one day:

A+B = 1/30 (that's mean only (1/30)*100 = 3.33% whole work done).

In order to complete the whole task is 100%.

So, 16A+44B = (100/100) = 1.

This explained why the number 1 exist in the equation. The other part can be solved on your own.

Selvi said:   2 decades ago
A having worked for 16 days
B finishes the remaining work alone in 44 days
so,
B finish the whole work alone is = A having worked+B finishes the remaining work alone
B alone = 16 days + 44 days
= 60 days

Vaibhav said:   10 years ago
A and B complete work in 30 days.

A+B = 30.

A finished work in 16 Days and Remaining worked finished by B in 44 days.

It means 16 + Remaining days = 44 days.

16-44 = 28 days.

So B takes 28 days to finish the work alone.

But A and B together Finished work in 30 days.

16+14 = 30.

If they work together it takes 14 days to complete remaining work.

But B takes 28 days it means.

Both together takes 30 days so only B will take 60 days to complete the work.

Sorry my thinking is different.

Sri said:   10 years ago
Please explain in LCM method.

Bala said:   10 years ago
@Varun method is short one but calculation will be difficult.

@Neha Varun convert A's 16 days work into percentage i.e 16/60 = 26.66.

Total working days A+B = 60.


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