Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
Then, x + y = | 1 | and 16x + 44y = 1. |
30 |
Solving these two equations, we get: x = | 1 | and y = | 1 |
60 | 60 |
![]() |
1 | . |
60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 8 of 10.
Bangaram said:
1 decade ago
Kanna your explaination was good.
Akiii said:
1 decade ago
Kanna you are right.
Vishal said:
1 decade ago
Above solution is not properly explained.
Let me try to make it more clear (mathematically or logically).
1 day = 24 Hours.
A worked x hours in 1 day (24 hours).
B worked y hours in 1 day (24 hours).
So, x + y = 24 hours ----- Eq 1.
Now A's 16 days' work in hours = 16 * x = 16x.
And B's 44 days' work in hours = 44 * y = 44y.
16x + 44y = 30 days together worked of A + B in hours = 30 * 24 = 720 hours.
So 16x + 44y = 720 ----- Eq 2.
Now Eq 2 - 16 * Eq 1.
16x + 44y = 720.
16x + 16y = 384.
0 + 28y = 336.
Y = 336 / 28 = 12 hours in 1 day.
So x = 12 hours in 1 day.
If A doesn't work then to B has to work 24 hours in order to finish 1 day work which is equal to 2 days for B.
So for 30 days work, B has to work 60 days (answer = 60 days).
Let me try to make it more clear (mathematically or logically).
1 day = 24 Hours.
A worked x hours in 1 day (24 hours).
B worked y hours in 1 day (24 hours).
So, x + y = 24 hours ----- Eq 1.
Now A's 16 days' work in hours = 16 * x = 16x.
And B's 44 days' work in hours = 44 * y = 44y.
16x + 44y = 30 days together worked of A + B in hours = 30 * 24 = 720 hours.
So 16x + 44y = 720 ----- Eq 2.
Now Eq 2 - 16 * Eq 1.
16x + 44y = 720.
16x + 16y = 384.
0 + 28y = 336.
Y = 336 / 28 = 12 hours in 1 day.
So x = 12 hours in 1 day.
If A doesn't work then to B has to work 24 hours in order to finish 1 day work which is equal to 2 days for B.
So for 30 days work, B has to work 60 days (answer = 60 days).
Guest said:
2 decades ago
Selvi: its wrong... because, we dont know a & b's one day work.
Sunil kumar said:
1 decade ago
Any easy method better than above all? All are did in same method. Somehow tough above all the methods.
Ray said:
10 years ago
I have figure out the easiest way to understand the equation:
Let's say the speed of work done by each A and B in one day:
A+B = 1/30 (that's mean only (1/30)*100 = 3.33% whole work done).
In order to complete the whole task is 100%.
So, 16A+44B = (100/100) = 1.
This explained why the number 1 exist in the equation. The other part can be solved on your own.
Let's say the speed of work done by each A and B in one day:
A+B = 1/30 (that's mean only (1/30)*100 = 3.33% whole work done).
In order to complete the whole task is 100%.
So, 16A+44B = (100/100) = 1.
This explained why the number 1 exist in the equation. The other part can be solved on your own.
Selvi said:
2 decades ago
A having worked for 16 days
B finishes the remaining work alone in 44 days
so,
B finish the whole work alone is = A having worked+B finishes the remaining work alone
B alone = 16 days + 44 days
= 60 days
B finishes the remaining work alone in 44 days
so,
B finish the whole work alone is = A having worked+B finishes the remaining work alone
B alone = 16 days + 44 days
= 60 days
Vaibhav said:
10 years ago
A and B complete work in 30 days.
A+B = 30.
A finished work in 16 Days and Remaining worked finished by B in 44 days.
It means 16 + Remaining days = 44 days.
16-44 = 28 days.
So B takes 28 days to finish the work alone.
But A and B together Finished work in 30 days.
16+14 = 30.
If they work together it takes 14 days to complete remaining work.
But B takes 28 days it means.
Both together takes 30 days so only B will take 60 days to complete the work.
Sorry my thinking is different.
A+B = 30.
A finished work in 16 Days and Remaining worked finished by B in 44 days.
It means 16 + Remaining days = 44 days.
16-44 = 28 days.
So B takes 28 days to finish the work alone.
But A and B together Finished work in 30 days.
16+14 = 30.
If they work together it takes 14 days to complete remaining work.
But B takes 28 days it means.
Both together takes 30 days so only B will take 60 days to complete the work.
Sorry my thinking is different.
Sri said:
10 years ago
Please explain in LCM method.
Bala said:
10 years ago
@Varun method is short one but calculation will be difficult.
@Neha Varun convert A's 16 days work into percentage i.e 16/60 = 26.66.
Total working days A+B = 60.
@Neha Varun convert A's 16 days work into percentage i.e 16/60 = 26.66.
Total working days A+B = 60.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers