Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
30 days
40 days
60 days
70 days
Answer: Option
Explanation:

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1 and 16x + 44y = 1.
30

Solving these two equations, we get: x = 1 and y = 1
60 60

B's 1 day's work = 1 .
60

Hence, B alone shall finish the whole work in 60 days.

Discussion:
97 comments Page 10 of 10.

Sakshi said:   1 decade ago
I can't understand. Why we have used x? We did not do this in other question.

Ram said:   1 decade ago
1/A + 1/B = 1/30 ------ 1.
16/A + 44/B = 1 ------- 2.

Solving these 2 equation:

B = 60.

IOvd said:   1 decade ago
@Sneha.

x+y = 1/30 .....(i).
16x+44y = 1 .....(ii).

Multiply equation (i) by 16 we get,

16x+16y = 8/15(ie 16/30).....(iii).

Now subtract equation (iii) from equation (ii).

16x+44y = 1.
- 16x+16y = 8/15.
-----------------
+28y = 7/15 (ie 1-8/15).

Now y = 7/15*1/28.
y = 1/15*1/4.
y = 1/60.

I hope u get it now.

Sneha said:   1 decade ago
Yet I don't get anything how the answer is 60. Please explain it.

x+y = 1/60 and 16x+44y = 1/60.

How it comes?

Shyam said:   1 decade ago
I got the same answer as Sai and Kaustubha.

Kaustubha Sen said:   1 decade ago
I think there is a mistake in the understanding.

"A having worked for 16 days, B finishes the remaining work alone in 44 days"

Look at this line.

- A worked for 16 days
- B finishes remaining work "ALONE" in 44 days.

So, it is never mentioned that A worked 16 days alone. I think it should be interpreted as - A worked with B for 16 days and then stopped. B did the remaining in 44 days.

Thus Solution is -

Let A's 1 day's work = x and B's 1 day's work = y

Then, x + y = 1/30 and 16*(x + y) + 44y = 1

Solving we get,

16 * (x + y) + 44y = 1.
or 16 * 1/30 + 44y = 1.
or 44y = 1 - 16/30.
or y = (14/30)/44.

Thus B finishes the work in (44 * 30)/14 = 94.285714.

Achesh said:   1 decade ago
This answer can still be solved by only having the basic formulas in mind.
Let A take x and B take y days to complete the whole work.

From question, we know,
1/x+1/y = 30 . By solving this we get,

xy = 30x+30y ... (1).

Now, work done by A in 1 day is 1/x. Therefore in 16 days = 16/x.
Remaining work = 1-(16/x).

This remaining work is done by B in 44 days.
And we have assumed that B takes y days to complete the job.

So for B.

WORK : Days
1 : y
1-(16/x) : 44

Solving this equation we get,
xy = 44x+16y ... (2).

Comparing (1) and (2),
30x+30y = 44x+16y.

Solve this and we get x=y.!
Put this in first equation , i.e.
1/y+1/y = 1/30.
2/y = 30.

Therefore, y = 60!
Hence 60 days.

Lengthy, but easy and precise :).


Post your comments here:

Your comments will be displayed after verification.