Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 30)
30.
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone?
Answer: Option
Explanation:
Let A's 1 day's work = x and B's 1 day's work = y.
| Then, x + y = | 1 | and 16x + 44y = 1. |
| 30 |
| Solving these two equations, we get: x = | 1 | and y = | 1 |
| 60 | 60 |
 B's 1 day's work = |
1 | . |
| 60 |
Hence, B alone shall finish the whole work in 60 days.
Discussion:
97 comments Page 4 of 10.
Sourabh sharma said:
5 years ago
Let total work = 30 units (As days are 30).
A+B = 30/30 i.e, they both do "1" unit of work.
If A works for 16 days i.e, he made "8" units only.
And B was left with 22 (30-8).
So, 22--> 44.
1--> 2.
ATQ, B's whole work alone:
30(total) * 2 = 60DAYS answer.
A+B = 30/30 i.e, they both do "1" unit of work.
If A works for 16 days i.e, he made "8" units only.
And B was left with 22 (30-8).
So, 22--> 44.
1--> 2.
ATQ, B's whole work alone:
30(total) * 2 = 60DAYS answer.
(5)
Pranav Jain said:
10 years ago
What happens if the third condition is implemented saying B and C completes work in 16 days and A works for 7 days, B for 5 and C alone completes remaining work for 13 days, then C alone can complete work in how many days, how to solve this, when another variable is involved?
Jyoti Singh said:
9 years ago
Can anyone tell how to solve efficiency questions of time & work?
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Like.
A is 140% efficient than B. B starts the work & does 5 days then A completes the remaining work in 10 days. In how many days does A take to complete the same work.
Please, anyone tell me.
Dhakshina said:
9 years ago
Given X + Y =30.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
They never mentioned any efficiency (like B is twice as good).
Assume that they are equal efficiency.
So A Did only 16 days work and B completed remaining work in 44 days.
Therefore total work of B is 44 + 16 = 60.
Total work of A is also 60.
Ebrahim said:
9 years ago
Guys this is very very simple.
Time taken by A + B : 30 days.
They didn't mention the efficiency of neither A nor B.
So we can take 50/50 efficiency.
For example
Total: 30 candles.
A+B making 30 candles in 30 days.
So, A alone makes 30 candles in 60 Days.
Time taken by A + B : 30 days.
They didn't mention the efficiency of neither A nor B.
So we can take 50/50 efficiency.
For example
Total: 30 candles.
A+B making 30 candles in 30 days.
So, A alone makes 30 candles in 60 Days.
Shraddha said:
1 decade ago
A's 16 days work + B's 44 days work = 1
(A+B) 16 days work + B's 28 days work = 1
but (A+B) 1 days work= 1/30
hence, (A+B) 16 days work = 8/15
therefore,
8/15 + B's 28 days work = 1
B's 28 days work = 1- 8/15
= 7/15
B's 1 days work = 1/60
(A+B) 16 days work + B's 28 days work = 1
but (A+B) 1 days work= 1/30
hence, (A+B) 16 days work = 8/15
therefore,
8/15 + B's 28 days work = 1
B's 28 days work = 1- 8/15
= 7/15
B's 1 days work = 1/60
Aakash said:
9 years ago
2 workers A + B together could finish a work in 8 days they work together for 6 days & A left the works the remaining works was completed by B alone in 6 days. How many days would each take to complete the individual?
How to solve this problem?
How to solve this problem?
Shraddha said:
1 decade ago
Multiply x+y=1/30 by 16 and that gives 16x+16y=8/15
subtract 16x + 16y = 8/15
-
16x + 44y =1
----------------
28y = 7/15
hence, y=1/60
substitute y= 1/60 in x+y=1/30 and we get, x=1/60
subtract 16x + 16y = 8/15
-
16x + 44y =1
----------------
28y = 7/15
hence, y=1/60
substitute y= 1/60 in x+y=1/30 and we get, x=1/60
Puneet negi said:
8 years ago
A + b=30.
Let the efficiency of a and b is 1.
Then total work will be 30*2=60.
A did 16 work then remaining work is,
60-16=44 which will be completed by b in 44 days so B's actual efficiency is 1 so B will finish 60 work in 60 days.
Let the efficiency of a and b is 1.
Then total work will be 30*2=60.
A did 16 work then remaining work is,
60-16=44 which will be completed by b in 44 days so B's actual efficiency is 1 so B will finish 60 work in 60 days.
Usha said:
1 decade ago
I agree with @Sunil kumar.
Why it has been calculated as x+y=1/30 instead of considering 1/x + 1/Y = 1/30.
Kindly explain, I understood the above calculations but the basic equation why it was altered that I din't got.
Why it has been calculated as x+y=1/30 instead of considering 1/x + 1/Y = 1/30.
Kindly explain, I understood the above calculations but the basic equation why it was altered that I din't got.
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