Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
284 comments Page 6 of 29.
Bindu said:
5 years ago
3/2 *60, how come 3/2?
Naga said:
5 years ago
The ratio of work done by A & B= 1:3.
(Because A is thrice as good as B)
A' s work done = Less than 60 days than B.
So take B's work done = x days---(1)
Then A's work done = x-60---(2)
So, 1=x-60,
3= x.
So cross mutiply as per the ratio simplification.
x * 1= 3(x-60),
x=3x-180,
3x-x=180,
x =90.
As per (1) & (2)
B's work done = 90 days,
A's work done = 90-60 = 30 days,
(A+B)'s 1 day work done = 1/30 +1/90=4/90=2/45,
Total work done = 45/2= 22 1/2 days.
(Because A is thrice as good as B)
A' s work done = Less than 60 days than B.
So take B's work done = x days---(1)
Then A's work done = x-60---(2)
So, 1=x-60,
3= x.
So cross mutiply as per the ratio simplification.
x * 1= 3(x-60),
x=3x-180,
3x-x=180,
x =90.
As per (1) & (2)
B's work done = 90 days,
A's work done = 90-60 = 30 days,
(A+B)'s 1 day work done = 1/30 +1/90=4/90=2/45,
Total work done = 45/2= 22 1/2 days.
Rajesh said:
6 years ago
Work=3:1.
Time 1:3.
2 part=60 (difference).
1 part=30.
1*30:3*30=30:90.
He asked work of B( 90)can do by both in how many days.
90/(1+3)= 90/4=22.5 days.
Time 1:3.
2 part=60 (difference).
1 part=30.
1*30:3*30=30:90.
He asked work of B( 90)can do by both in how many days.
90/(1+3)= 90/4=22.5 days.
(1)
MOSA said:
6 years ago
Let a did this work in X days.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
B can do it in 3x days.
X+60=3x.
X=30.
It means A can complete this work in 30 days and B in 90 days;
Capacity of;
A is 3.
B is 4.
A+B= 4.
TIME =90/4.
Abhijith said:
6 years ago
Can someone provide a solution for this problem using percentages or the efficiency ration ?
Priti said:
6 years ago
***shortcut method******
D= no of days.
n= n times as fast.
D*n/n^2-1
60*3/3^2-1
180/9-1
180/8=90/4=22 1/2.
D= no of days.
n= n times as fast.
D*n/n^2-1
60*3/3^2-1
180/9-1
180/8=90/4=22 1/2.
Dinesh said:
6 years ago
Please tell how A is working 30 days. How we calculate I don't understand.
Aravind said:
6 years ago
Hi, friends, it's a bit tricky.
First, they found the time difference to do work between a and b.
Because the data we have is time difference in qn for 60 days consider.
Then. If a takes 1 day. B takes 3 days. So.
For 2 days time difference : 3 days for b
Then multiply both sides by 30 since the time difference is given
For 60 days time difference: 90 days of b.
I hope you all get it.
Then use ratio. A takes 30 days to complete work.
First, they found the time difference to do work between a and b.
Because the data we have is time difference in qn for 60 days consider.
Then. If a takes 1 day. B takes 3 days. So.
For 2 days time difference : 3 days for b
Then multiply both sides by 30 since the time difference is given
For 60 days time difference: 90 days of b.
I hope you all get it.
Then use ratio. A takes 30 days to complete work.
Rohan said:
6 years ago
A and B
Work 3:1
Time 1:3
i.e. 30:90 ......multiply by 30.
And also they have given that the difference between the time taken to complete the work is 60.
Hence when A and B time to work together,
1/30+ 1/90 = 2/45,
Defer for A and B to complete the entire work they require 45/2 which is equivalent to 22 and A half-day.
Work 3:1
Time 1:3
i.e. 30:90 ......multiply by 30.
And also they have given that the difference between the time taken to complete the work is 60.
Hence when A and B time to work together,
1/30+ 1/90 = 2/45,
Defer for A and B to complete the entire work they require 45/2 which is equivalent to 22 and A half-day.
Sanishk said:
6 years ago
What is wrong with the below step?
A's 1-day work = 1/y.
Then, B's 1-day work = 1/3y.
Now,
A completes work before 60 days compared to B.
So,
1/y - 1/3y = 1/60
2/3y = 1/60
y = 40.
i.e., A completes in 40 days and B completes in 120 days,
Now, working together they complete in
1/A + 1/B = 1/40+ 1/120 = 1/30.
So, Together they complete in 30 days.
A's 1-day work = 1/y.
Then, B's 1-day work = 1/3y.
Now,
A completes work before 60 days compared to B.
So,
1/y - 1/3y = 1/60
2/3y = 1/60
y = 40.
i.e., A completes in 40 days and B completes in 120 days,
Now, working together they complete in
1/A + 1/B = 1/40+ 1/120 = 1/30.
So, Together they complete in 30 days.
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A and B together can do the work in