Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes | ![]() |
3 | x 60 | ![]() |
= 90 days. |
2 |
So, A takes 30 days to do the work.
A's 1 day's work = | 1 |
30 |
B's 1 day's work = | 1 |
90 |
(A + B)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 4 | = | 2 |
30 | 90 | 90 | 45 |
![]() |
45 | = 22 | 1 | days. |
2 | 2 |
Discussion:
281 comments Page 27 of 29.
Bhupinder said:
10 years ago
Good explanations thanks.
Purusottam said:
8 years ago
Yes, correct @Sugumaran.
Varma said:
1 decade ago
Nice formula @Sheetal.
Mohit said:
7 years ago
3 x 60/3^2-1 = 22 1/2.
Bindu said:
5 years ago
3/2 *60, how come 3/2?
Michael said:
1 decade ago
How do we get 4/90 ?
Chacha said:
6 years ago
It's simply.
3a = b.
3a = b.
Sherin said:
8 years ago
Thank you @Showry.
Sangeetha said:
2 decades ago
Oh thanks sheetal
Praveen said:
1 decade ago
Nice exp. Harsha.
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