Aptitude - Time and Work - Discussion

Guys check this out and don't be confused....
as we know A is 3 time better than B and A takes 60 days less than B so, time taken by A: time taken by B= 1:3
= b-60:b ( suppose time by B is b)
by cross multiply, 3b-180=b
i.e. b=90 so time taken by B=90
and time taken by the A is=90-60= 30

Thanks sheetal.

Nice formula @Sheetal.

Another easy way 2 find out:

1st put the ratio i.e.1:3(A:B)
2nd the condition given here is A can work less than 60 days

So, find out the probability that matches with the ratio condition(A&B must be difference 60 here) for eg:let we take as A as 20 therefore B must be 60(here we get the difference as 40 only)according to 1:3 which cant satisfy

The given condition(A less than B by 60 days) suppose you take A as 30 means you get B as 90 which is greater than 60 days
of A....A=30 B=90 A's 1 day work=1/30

B's 1 day work=1/90 A+B's 1 day work =1/30+1/90=4/90 here they are not given to find out as 1day work...so take as 90/4=22.5 <==> 22(1/2).

@Neeraj-A will finish the work 60 days lesser than B,means if B takes 60 days to complete the work,A takes 1 day.

A will finish the work 60 days lesser than B.

What is it mean please explain?

Thanks harsha.

Thanks Showry for given the simple and correct ans.

Awesome explanation HARSHA

Ratio of times taken by A and B = 1 : 3.

That is If A takes 1 day B takes 3 days
Time Difference is 3-1 = 2 days

Here is the tricky part :
If A takes 1/2 day B takes 3/2 days
Time Difference is 3/2 - 1/2 = 1 days

When time difference is 60 days (Just mulitply by 60)
A takes 60/2 and B takes 3*60/2

So, A takes 30 days to do the work.
and B takes 90 days to do the work.

A's 1 day's work = 1/30
B's 1 day's work = 1/90

(A + B)'s 1 day's work = (1/30 + 1/90)= 4/90 = 2/45

A and B together can do the work in 45/2 = 22+1/2