Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Answer: Option
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes |  |
3 | x 60 |  |
= 90 days. |
| 2 |
So, A takes 30 days to do the work.
| A's 1 day's work = | 1 |
| 30 |
| B's 1 day's work = | 1 |
| 90 |
| (A + B)'s 1 day's work = | |
1 | + | 1 | |
= | 4 | = | 2 |
| 30 | 90 | 90 | 45 |
 A and B together can do the work in |
45 | = 22 | 1 | days. |
| 2 | 2 |
Discussion:
287 comments Page 22 of 29.
Yash said:
7 years ago
(T*T.D)/(T^2-1).
T-EFFICIENCY.
T.D-TIME DIFFERENCE.
So;
3*60/9-1 = 22.5.
T-EFFICIENCY.
T.D-TIME DIFFERENCE.
So;
3*60/9-1 = 22.5.
Dinesh said:
6 years ago
Please tell how A is working 30 days. How we calculate I don't understand.
Pavethra said:
1 decade ago
I tell that A is thrice as good as B so it should be 3:1 na.
Am I right?
Am I right?
Shro said:
1 decade ago
Indhu very easy simple explanation as per the question.
Good :) thanku :)
Good :) thanku :)
Lins said:
1 decade ago
1:3 = x:(x+60).
1/3 = x/(x+60).
So x+60 = 3x.
60 = 2x.
Then x = 30.
1/3 = x/(x+60).
So x+60 = 3x.
60 = 2x.
Then x = 30.
Abdul said:
1 decade ago
Hey Siva your way of solving is fantastic and understandable! Thanks.
Devendra kumar said:
9 years ago
Please tell me the easiest solution of this problem. Like LCM method.
Saikrishna said:
8 years ago
a b
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
x 3x
2x=60 so x=30
total work=3*30=90
Ans=90/4=22 1/2.
Rajender said:
2 decades ago
Please tell me how you have calculated differece of time 2 days.
(1)
Keerthi said:
1 decade ago
So by the explanation above we have to take in the ratio 1:3.
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