Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 4)
4.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
20 days
22 1 days
2
25 days
30 days
Answer: Option
Explanation:

Ratio of times taken by A and B = 1 : 3.

The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes 3 x 60 = 90 days.
2

So, A takes 30 days to do the work.

A's 1 day's work = 1
30

B's 1 day's work = 1
90

(A + B)'s 1 day's work = 1 + 1 = 4 = 2
30 90 90 45

A and B together can do the work in 45 = 22 1 days.
2 2

Discussion:
281 comments Page 14 of 29.

Anshul said:   10 years ago
We can solve this question easily.

A:B = 1:3.

Difference is 60.

Hence ratio becomes:

A:B = 30:90 = 1:3.

Here we can see diff is 60.

So our answer will be 90*30/90+30 = 270/12.

= 90/4 = 45/2 = 22+1/2.

Salman said:   10 years ago
So much confusing answer given. This is basically ratio problem.

60 days less means you have to take ratio of time and solve the problem. A is thrice as better as B means. B takes thrice time compared to A.

i.e Ratio of time taken by A/B = 1/3.

If B takes x days then A takes x-60 days time to complete the work.

i.e Ratio of time taken by A/B = x-60/x.

Therefore 1/3 = x-60/x.

Solve to get x = 90 therefore B takes 90 days and A takes 30 days.

Daily Work of A = 1/30.

Daily Work of B = 1/90.

Adding work of A and B.

Daily work of A and B is 4/90.

So time taken for both A and B to complete the work is 90/4 = 221/2 days!

Simple as that!

Nilu said:   10 years ago
A is thrice good as B.

So, ratio of work done is 3:1 and A taken 60 days less as compare to B.

Let time taken by B is x so time taken by A is x-60.

So 3:1::x:x-60.

3x-180 = x. So 2x = 180 and x = 90.

Time taken by B = 90 days so time taken By A is 30 days.

A's one day work = 1/30 and B's one day work is 1/90.

Total work done by both A and B in one day = 1/30+1/90.

= 3+1/90 = 4/90 = 2/45 = 22.5 days.

Pratim Pal said:   10 years ago
Hi friend.

This is one of easiest problem.

Here given that the ratio of time taken of A and B to complete one work in individually is 1:3.

So let us take A can do this work in X days and that of B is 3X days.

According to conditions B took 60 days more than A.

3X-X = 60.

2*X = 60.

X = 30.

So time taken by B is 3*30 = 90 days and by A is 30 days.

When A&B together do this work. The required time is:

= 1/(1/30+1/90).

= 1/((3+1)/90).

= 45/2 days.

Sagar said:   10 years ago
Please tell me how is the difference of time is 60 days?

Sudip purakait said:   10 years ago
Hi @Sagar.

It is mentioned in the question.

Mukunda saini said:   10 years ago
A is thrice as good as B. So A = 3x and B = x.

A is 60 greater than B. So 3x-x = 60.

2x = 60.

x = 30.

A = 90 and B = 30.

1/90+1/30 = 45/2.

Answer: 22 1/2.

Sravan said:   10 years ago
Since it's mentioned that A completed 60 days less than B.

We have to know there less than rate. Since it given A is thrice as good as B.

That means it takes 1 day to A to do Bs 3 day work.

So now we can know that A can do in (3-1) = 2 days less than B.

That means A less than days for B days for 2 its 3.

Similarly for 60 less day we need to multiply 2 by 30 to get 60. Since we do on 2 (A) side we have to multiply on 3 (B) side then we get.

= 2x30 : 3x30.

We get = 60 (for A day's lesser than B) : 90 (we got B days) that means A work days = 90-60 = 30.

So 1/30 + 1/90= 0.0444 amount of work per 1 day.

For 1 piece of complete work 0.4444/0.4444 = 1/0.4444 days.

That 1 piece of work done for 22.5 days by A & B together.

Bhupinder said:   10 years ago
Good explanations thanks.

Vamshidhar said:   10 years ago
In the explanation, said that,

"If difference of time is 60 days, B takes (3/2*60) = 90 days.

My opinion is if A can complete work in 60 days then B should complete work in 3*60 = 180 days but not in 90 days.

Can anyone explain this part?


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