Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 21)
21.
A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:
4 days
6 days
8 days
12 days
Answer: Option
Explanation:

Suppose A, B and C take x, x and x days respectively to finish the work.
2 3

Then, 1 + 2 + 3 = 1
x x x 2

6 = 1
x 2

x = 12.

So, B takes (12/2) = 6 days to finish the work.

Discussion:
68 comments Page 6 of 7.

Rajshekar said:   6 years ago
A x.
B 2x.
C 3x.

A+B+B = 1/2,
X+2x+3x = 1/2.
6x=1/2.
X=1/12.

So, be alone =2x = 2 * 1/12 = 1/6 = 6days.
(9)

G JOGI RAO said:   10 years ago
Hi @Kiran.

If 6A = 2 then A = 3.

But you said it A = 12 give proper explanation?

Srihari said:   1 decade ago
Hi Meera,

It is not right method because A+B+C's 1 day work is only 1/2 not 1/6.

Ananth said:   1 decade ago
How the total work equation became as (1/x)+(2/x)+(3/x)=1/2

Please explain.

Banjeet said:   4 years ago
A : B : C = 6 : 3 : 2,
11*2= 22 work,
So, B doing = (3/11) * 22 = 6 days.
(22)

Raj said:   8 years ago
@Ravi.

Where you get 12 unit work in 1 days and how please explain it?

Pushpendra said:   8 years ago
Yes, right @Ravi.

Your method of explanation is clear, Thanks @Subhas.

Loki said:   8 years ago
a+2a+3a = 2days.
6a = 2days,
a = 1/3(this is total),
3*2 = 6.

Kumar said:   1 decade ago
How the work equation became as (1/x)+(2/x)+(3/x)=1/2

Bulu said:   7 years ago
@Manish, @Kiran.

Thanks for explaining the solution.


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