Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
210 comments Page 9 of 21.
Sami said:
7 years ago
Speed = distance/time.
Time = distance/speed.
Speed=600-200 = 400 km/hr.
Distance to cover = 600 km.
Duration required(time) = 600/400 = 3/2 hr.
3/2*60 = 60 min = 1hr.
Time = distance/speed.
Speed=600-200 = 400 km/hr.
Distance to cover = 600 km.
Duration required(time) = 600/400 = 3/2 hr.
3/2*60 = 60 min = 1hr.
(4)
Amala said:
1 decade ago
@Mr. saravanagopi,
we already calculate the time as x+30 in [200(x+30)=600] right. then why did you again calculating the result as 27+30.
I don't understand...
we already calculate the time as x+30 in [200(x+30)=600] right. then why did you again calculating the result as 27+30.
I don't understand...
Uday said:
1 decade ago
I have a quest actually the time is x+1/2 hours after delay that's the whole duration of flight but its taken as only x now its actually x+1/2 = 1 and half hour.
Pavan said:
2 decades ago
Helloo kiran I have 1 doubt you say that x is in hr so 3 you taken as x/2 but we dnt't know what is x value it may be 2hr 3hr. Then how you will take 3min=x/2.
Bhavana said:
2 decades ago
2x2 + x - 3 = 0.
2x2 - 2x + 3x - 3 = 0.
2x(x - 1) + 3(x- 1) = 0.
(2x + 3) (x - 1) = 0.
X=3/2 or x=1.
Hope you got d answer Sundar.
2x2 - 2x + 3x - 3 = 0.
2x(x - 1) + 3(x- 1) = 0.
(2x + 3) (x - 1) = 0.
X=3/2 or x=1.
Hope you got d answer Sundar.
AnilKumarReddy said:
1 decade ago
When solving the equation 2x^2+x-3 = 0.
We get two factors for x = 1 and x = -3/2.
Here time is always positive. So we are taking x = 1 there is no logic.
We get two factors for x = 1 and x = -3/2.
Here time is always positive. So we are taking x = 1 there is no logic.
Nitu said:
5 years ago
600/x - 1200/2x+1 = 200.
Lcm is
You get (2x+1)(600) - 1200x = 200(2x^2 +x).
1200x+600-1200x = 200(2x^2 +x),
600/200(2x^2+1),
3/(2x^2+x),
2x^2+x = 3.
X = 1.
Lcm is
You get (2x+1)(600) - 1200x = 200(2x^2 +x).
1200x+600-1200x = 200(2x^2 +x),
600/200(2x^2+1),
3/(2x^2+x),
2x^2+x = 3.
X = 1.
(8)
Azly said:
1 decade ago
Friends, we have to use trigonometry to solve this problems. And why they have mentioned average speed is reduced by 200 km/h since it the reduced "speed".
Nitin Kataria said:
2 years ago
New speed (old speed - change in speed) = ΔS/ΔT.
200/.5h = 400km/h.
new time(old time + extra time) = 600/400 = 1.5h,
Initial time is taken 1.5 - 0.5 = 1h.
200/.5h = 400km/h.
new time(old time + extra time) = 600/400 = 1.5h,
Initial time is taken 1.5 - 0.5 = 1h.
(45)
Arun said:
8 years ago
If the average speed is increased by 200km/hr and time of flight is decreased by 30mins. What is the equation?
(600/x)-(600/x+1/2))=-200 is this correct?
(600/x)-(600/x+1/2))=-200 is this correct?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers