Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
1 hour
2 hours
3 hours
4 hours
Answer: Option
Explanation:

Let the duration of the flight be x hours.

Then, 600 - 600 = 200
x x + (1/2)

600 - 1200 = 200
x 2x + 1

x(2x + 1) = 3

2x2 + x - 3 = 0

(2x + 3)(x - 1) = 0

x = 1 hr.      [neglecting the -ve value of x]

Discussion:
210 comments Page 12 of 21.

Karthilk said:   1 decade ago
A car travelling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car?

Sneha said:   9 years ago
600(2x+1)-1200x=200x(2x+1).
1200x+600-1200x=400x^2+200x.
600=400x^2+200x,
300=200x^2+100,
3=2x^2+x,
2x^2+x-3=0.

Shwetank Agarwal said:   1 decade ago
The distance is same in both cases and let time in case 1 be t.

Then 600 t = 400 (t+30/60).

Thus t = 1 hr.

Nivas said:   1 decade ago
@saravanakgopi.

What he said is wrong. Because he didn't convert hr into min. So that his method is wrong.

Zary said:   2 decades ago
Hi frnds! I'm not getting why you are taking.

600 - 600 = 200.

X x + (1/2) ?

Please explain in detail!

Kush said:   1 decade ago
Why there is always subtraction in the formula?

i.e. 600/x - 600/(x+.5) = 200.

Why "-" ?

Srinu said:   9 years ago
Why should we take the diff between the velocity's as reduced speed?

Please briefly explain any one.

Mary grace said:   3 years ago
D = 600km.
Speed = 200km/hr,
Time = ?( 30 mins increases).
30T = d/s.
30t = 600/200.
30t = 3,
T = 1.
(209)

Babita said:   1 decade ago
@Manik , Sunita ,
200 = 600/x+30
200(x+30)=600
200x+6000=600
200x=600-6000
200x=5400
x=5400/200
x=27

Shyam kumar said:   2 years ago
D = S * T.
600 = 200 * (T+30),
600/200 = T+30.
T = 27.
TOTAL DURATION = T+30= 27+30 = 57 ~1HOUR.
(123)


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