Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 6)
6.
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
Answer: Option
Explanation:
Let the duration of the flight be x hours.
| Then, | 600 | - | 600 | = 200 |
| x | x + (1/2) |
 |
600 | - | 1200 | = 200 |
| x | 2x + 1 |
x(2x + 1) = 3
2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr. [neglecting the -ve value of x]
Discussion:
206 comments Page 11 of 21.
Murad Hossain said:
8 years ago
Suppose,
Duration = x hour.
600-200 = 400,
ATq,
x/400 - x/600 = 1/2,
2x = 1200,
x = 600,
So,
duration = 600/600 = 1 hour.
Duration = x hour.
600-200 = 400,
ATq,
x/400 - x/600 = 1/2,
2x = 1200,
x = 600,
So,
duration = 600/600 = 1 hour.
Sundar raj said:
2 decades ago
@Kiran
your answer is right only. But can you briefly explain how to find the value X from 2x2 + x - 3 = 0.
your answer is right only. But can you briefly explain how to find the value X from 2x2 + x - 3 = 0.
(1)
Patreppa said:
8 years ago
Yesh, I understood till,
(600/x) - (1200/(2x+1)) = 200.
Please, can anybody simplify this, only let me know, please.
(600/x) - (1200/(2x+1)) = 200.
Please, can anybody simplify this, only let me know, please.
Srinath said:
1 decade ago
Generally time taken to travel 600 km with 200 kmph will take 3 hr journey but how the time of flight will be 1 hr.
MALLIKARJUN said:
1 decade ago
Simple method.
200 km......> 30 min (30/60 h).
Then 600......> ?
Therefore 600*30/60 = x*200.
x = 60 min.
200 km......> 30 min (30/60 h).
Then 600......> ?
Therefore 600*30/60 = x*200.
x = 60 min.
Surya said:
8 years ago
S inversely proportional to time;
Time increases flight speed decreases
T1s1=T2S2
X*600=(x+30)400
6x=4x+120
X=60.
Time increases flight speed decreases
T1s1=T2S2
X*600=(x+30)400
6x=4x+120
X=60.
(1)
Karthilk said:
1 decade ago
A car travelling with of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the car?
Sneha said:
8 years ago
600(2x+1)-1200x=200x(2x+1).
1200x+600-1200x=400x^2+200x.
600=400x^2+200x,
300=200x^2+100,
3=2x^2+x,
2x^2+x-3=0.
1200x+600-1200x=400x^2+200x.
600=400x^2+200x,
300=200x^2+100,
3=2x^2+x,
2x^2+x-3=0.
Shwetank Agarwal said:
10 years ago
The distance is same in both cases and let time in case 1 be t.
Then 600 t = 400 (t+30/60).
Thus t = 1 hr.
Then 600 t = 400 (t+30/60).
Thus t = 1 hr.
Nivas said:
1 decade ago
@saravanakgopi.
What he said is wrong. Because he didn't convert hr into min. So that his method is wrong.
What he said is wrong. Because he didn't convert hr into min. So that his method is wrong.
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