Aptitude - Time and Distance - Discussion

How will 2x+1 will come it it 600/(x+1/2) = 1200/x+1?

Guys I don't understand this problem. Surely if you were to do the original trip at an average speed of 600 km/hr then you would do it in 1 hr, yes?

Then you reduced your average speed by 200 km/hr to 400 km/hr which would mean 600 km would take 1 hr 30 min at the new average speed, ergo increasing your time by 30 min.

So the trip would then take an hour and a half not an hour, so what am I missing? Or is the question asking for the original time of the trip.

The distance is same in both cases and let time in case 1 be t.

Then 600 t = 400 (t+30/60).

Thus t = 1 hr.

In this question I have a doubt its average speed for the trip was reduced by 200 km/hr i.e., trip means both upside and downside distance. Such that the distance is 1200 km (600 km for upside and 600 km for downside).

I have a doubt in the question its average speed for the trip was reduced by 200 km/hr is given but trip means both up and down so that its 1200 kms but in the answer only 600 km is taken.

I have a quest actually the time is x+1/2 hours after delay that's the whole duration of flight but its taken as only x now its actually x+1/2 = 1 and half hour.

Hello friends.

Here D = 600 km.

Average speed = 200.

Here in the problem he did not mentioned about time so lets take it as x.

But he given increased time as 30 min.

So according to the problem actual time = x+30 min.

So, he is asking duration T=D/S.

x+30 = 600/200.

x+30 = 3.

x = 30-3 = 27 min.

But actual time = x+30 = 27+30 = 57 min approx 1 hr.

x-2x+2x+x/x+x+1, please solve this problem.

x-2x+2x+x/x+x+1, please solve this problem.

How you take 1200/2x +1? If you get 1200 then how its possible 2x+1.