Aptitude - Time and Distance - Discussion

How come 3 here? Please explain.

Let the speed of Abhay be X kmph.
Let the Time taken by Sameer to cover a distance of 30 km be T hr.
According to problem;

Abhay takes 2hr more than Sameer i.e, (T+2)
Speed =Distance/Time .
Abhay's speed = total distance/ time taken by Abhay.

X=30/(T+2) --------> eqn1.

Now,
If Abhay doubles his speed i.e, 2X he would take 1 hr less than Sameer i.e (T-1)
2X=30/(T-1)--------> eqn1.

Now divide eqn1/ eqn2.
You will get T = 4hr.
Now put T=4 in eqn1. You will get X = 5kmph.

By applying direct formulation speed - distance /time.
30/3 * 2,
= 5.

How that 6x came. Please can You explain. I Don't know That method.

I cant understand how it gets value 3 can any one make me clear to understand this please.

Anyone please explain in detail this problem.

Thanx DEVI you are great.

@thiru.g.

Thank you.

Thanks devi:).

Thanks devi. Great explanation.