Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 21 of 21.
Aishwarya said:
5 years ago
Well explanation, Thanks @Devi.
Shubham Patil said:
5 years ago
Thanks all.
Tripu said:
5 years ago
Thanks @Devi.
Himanshu said:
5 years ago
@All.
Simply, the solution is;
Abhay's doubled speed is = to the speed required to cover 30km in 3 hrs.
2x=30/3,
x= 10/2,
x= 5 km/hr,
Another way to solve is;
(30/x)-(30/2x) = 3.
30((1/x)-(1/2x)) = 3.
1/2x = 1/10.
2x = 10.
x = 5 km/hr.
Simply, the solution is;
Abhay's doubled speed is = to the speed required to cover 30km in 3 hrs.
2x=30/3,
x= 10/2,
x= 5 km/hr,
Another way to solve is;
(30/x)-(30/2x) = 3.
30((1/x)-(1/2x)) = 3.
1/2x = 1/10.
2x = 10.
x = 5 km/hr.
Palash said:
5 years ago
Abhay speed is getting double it means it will become Sameer = 2 Abhay and let us take Abhay as x then sameer will become 2x then add speed x+2x = 3x.
Harsh said:
5 years ago
Let's make it simple.
Let Abhay speed be x and Sameer be y
Equation 1be like this:
30/x - 30/y = 2.
Equation 2 be like this;
30/2x - 30/y = - 1(its because the double speed of Abhay than Sameer make a difference of 1 hour, i.e, Abhay take less time than Sameer that's why I put - 1).
On Solving both the equation you get something like this;
-30y= - 6xy.
6x=30 or x=5.
Let Abhay speed be x and Sameer be y
Equation 1be like this:
30/x - 30/y = 2.
Equation 2 be like this;
30/2x - 30/y = - 1(its because the double speed of Abhay than Sameer make a difference of 1 hour, i.e, Abhay take less time than Sameer that's why I put - 1).
On Solving both the equation you get something like this;
-30y= - 6xy.
6x=30 or x=5.
Paawan said:
5 years ago
Thanks for the solution @Devi.
Meenakshi said:
4 years ago
Actually use simple logic.
Initially, he took 2 hrs more than Sameer, then he took one hr less.
which means the difference in time that has occurred in 3hrs.
So, Intial time - final time = 3hrs.
Initially, he took 2 hrs more than Sameer, then he took one hr less.
which means the difference in time that has occurred in 3hrs.
So, Intial time - final time = 3hrs.
Ketan said:
4 years ago
Thanks @Devi.
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