Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 1 of 21.
Zary said:
2 decades ago
Hello I'm not getin from were do that "3" comes in second line.
Please explain in detaail!
Please explain in detaail!
(1)
Thiru.G said:
2 decades ago
If suppose x speet abay cover in y+2 time .
then 2x speed he covered in y-1.(here y is sameer to cover time).
then diirent between time = (y+2)-(y-1)=3.so
first covered time - second covered time = 3.
then 2x speed he covered in y-1.(here y is sameer to cover time).
then diirent between time = (y+2)-(y-1)=3.so
first covered time - second covered time = 3.
(2)
Arun said:
2 decades ago
How that 6x came. Please can You explain. I Don't know That method.
Anu said:
2 decades ago
Take L.C.M arun ji.... u can understand from whr do 6x came...!!!!
(1)
Anitha said:
1 decade ago
30/x-30/2x=3
=> 30/x-15/x=3
=> 15/x=3
=> 15=3x
=> 15/3=x
=> 5=x
=> 30/x-15/x=3
=> 15/x=3
=> 15=3x
=> 15/3=x
=> 5=x
(1)
Ranjit said:
1 decade ago
I cant understand how it gets value 3 can any one make me clear to understand this please.
Ram said:
1 decade ago
A bit confusing.
(1)
Sudha said:
1 decade ago
Anyone please explain in detail this problem.
Devi said:
1 decade ago
Distance=30km/hr
time taken by Sameer is t
Abhay travelling with a Speed X
Case 1:
time taken by Abhay to cover 30km is 30/X = t+2
Case 2(doubles speed):
time taken by Abhay to cover 30km is 30/2X = t-1
(30/X)- (30/2X) = (t+2)-(t-1)
(30/X) - (30/2X) = t+2-t+1
(30*2X) - (30*X) = 3 (2X^2) //LCM
60X - 30X = 6 X^2
30X = 6 X^2
30 = 6 X
X = 5
time taken by Sameer is t
Abhay travelling with a Speed X
Case 1:
time taken by Abhay to cover 30km is 30/X = t+2
Case 2(doubles speed):
time taken by Abhay to cover 30km is 30/2X = t-1
(30/X)- (30/2X) = (t+2)-(t-1)
(30/X) - (30/2X) = t+2-t+1
(30*2X) - (30*X) = 3 (2X^2) //LCM
60X - 30X = 6 X^2
30X = 6 X^2
30 = 6 X
X = 5
(1)
Noufal said:
1 decade ago
Thanx DEVI you are great.
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