Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
211 comments Page 22 of 22.
Asritha lalam said:
4 weeks ago
Here's Step by step explanation of the solution:
The Distance is equal for both --> D = 30 km,
Let the time taken by Sameer (T)= x.
So, time taken by Abhay = x+2 --> (2hrs more than sameer).
We know Distance and Time, so we can calculate speed i.e S=D/T.
Let the speed of Abhay (S) = 30/x+2-->[1]
Given that,
if Abhay doubles his speed --> new speed of Abhay = 2s.
He will take 1hr less than sameer --> now time taken by Abhay = x-1.
As S = D/T.
New speed of Abhay is calculated as -
2s = 30/x-1 -->[2]
Substitute the above 's' value of [1] in the '2s' value of [2]
2(30/x+2) = 30/x-1.
By solving, we get x=4 --> time taken by Sameer.
So, time taken by Abhay = x+2 = 4+2 = 6.
Now, speed of Abhay = 30/6 = 5kmph.
Thank you.
The Distance is equal for both --> D = 30 km,
Let the time taken by Sameer (T)= x.
So, time taken by Abhay = x+2 --> (2hrs more than sameer).
We know Distance and Time, so we can calculate speed i.e S=D/T.
Let the speed of Abhay (S) = 30/x+2-->[1]
Given that,
if Abhay doubles his speed --> new speed of Abhay = 2s.
He will take 1hr less than sameer --> now time taken by Abhay = x-1.
As S = D/T.
New speed of Abhay is calculated as -
2s = 30/x-1 -->[2]
Substitute the above 's' value of [1] in the '2s' value of [2]
2(30/x+2) = 30/x-1.
By solving, we get x=4 --> time taken by Sameer.
So, time taken by Abhay = x+2 = 4+2 = 6.
Now, speed of Abhay = 30/6 = 5kmph.
Thank you.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers