Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 11)
11.
In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
Answer: Option
Explanation:
Let Abhay's speed be x km/hr.
| Then, | 30 | - | 30 | = 3 |
| x | 2x |
6x = 30
x = 5 km/hr.
Discussion:
209 comments Page 11 of 21.
Prakash said:
1 decade ago
Its given that Abhay takes 2 hours more than Sameer. Then it should be x+2 instead of 2x. Am I right?
Zary said:
2 decades ago
Hello I'm not getin from were do that "3" comes in second line.
Please explain in detaail!
Please explain in detaail!
(1)
Ani said:
1 decade ago
Can any one use proper formula of maths to solve this question because it is all confusing?
Ranjit said:
1 decade ago
I cant understand how it gets value 3 can any one make me clear to understand this please.
Mostafa kamal Abir said:
1 month ago
Speed => 1 : 2.
Time => 2 : 1 = 6 : 3.
So, Required Distance = 30/6 = 5 km/h (Ans.)
Time => 2 : 1 = 6 : 3.
So, Required Distance = 30/6 = 5 km/h (Ans.)
(2)
Archna said:
8 years ago
Let's speed of Abhay is x.
Then 30/x-30/2x=3,
30/x-15/x=3,
15/x=3,
X=15/3,
X=5 answer.
Then 30/x-30/2x=3,
30/x-15/x=3,
15/x=3,
X=15/3,
X=5 answer.
Chandru said:
8 years ago
30/x-30/2x=3.
2*30/2*x-30/2x=3.
60/2x-30/2x=3.
30/2x=3
30=3*2x
30=6x,
x=30/6,
x=5kmph.
2*30/2*x-30/2x=3.
60/2x-30/2x=3.
30/2x=3
30=3*2x
30=6x,
x=30/6,
x=5kmph.
Kumr said:
1 decade ago
How equal to 3. More than sameer in 2 hours after less than sameer 1 hr why its came?
Gramophone said:
3 years ago
t+2 = 30/s ----> 1
t-1 = 30/2s ---- > 2
Solving this equation, we get;
s = 5.
t-1 = 30/2s ---- > 2
Solving this equation, we get;
s = 5.
(32)
Gayu said:
1 decade ago
Hello I'm not getting from were do that "3" comes in second line. Please explain.
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